⚠️SIMPLE QUESTION!⚠️ Write two ratios that are equivalent to 2:6.

Mathematics

1 answer:

Nikitich [7]3 years ago

3 0

Answer:

4:12 6:18 :) I hope this is ok (I haven't done ratios in a while lol)

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What is the unknown fraction? <br><br>6/10 + ____ = 62/100

sergeinik [125]

The answer is 2/100 or 1/50!

6/10 is equivalent to 60/100.
62/100 - 60/100 = 2/100 = 1/50

So, 6/10 + 1/50 = 62/100
6/10 + 2/100 = 62/100

(Use 1/50 because that’s the simplified answer!)

I hope this made sense! Good luck!

4 0

2 years ago

the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width

-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

$\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}$

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

$\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}$

On solving the above expression for x we get

$\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}$

$\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}$