An unknown radioactive substance has a half-life of 3.20 hours . If 16.5 g of the substance is currently present, what mass A0 w
1 answer:
You might be interested in
Answer : The full balanced ionic equation will be,
Reactants are lead nitrate and potassium iodide.
Products are lead iodide and potassium nitrate.
The spectator ions are,
Explanation :
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
When potassium iodide react with lead nitrate then it gives potassium nitrate and lead iodide as a product.
The full balanced ionic equation will be,
The ionic equation in separated aqueous solution will be,
In this equation, are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
Answer : The ratio of the protonated to the deprotonated form of the acid is, 100
Explanation : Given,
pH = 6.0
To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :
Now put all the given values in this expression, we get:
As per question, the ratio of the protonated to the deprotonated form of the acid will be:
Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100