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Keith_Richards [23]
3 years ago
6

Fill in the left side of this equilibrium constant equation for the reaction of acetic acid HCH3CO2 with water.

Chemistry
1 answer:
Luda [366]3 years ago
5 0

Answer:

The left side equation is:

Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}

Explanation:

For the reaction of acetic acid HCH3CO2 with the water, The equilibrium constant equation is

HCH_{3}COO + H_{2}O \rightleftharpoons CH_{3}COO^{-} + H_{3}O

The left side of this equilibrium constant equation will be written as shown below:

Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}

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