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Alecsey [184]
3 years ago
5

Question 8 pls help me please

Mathematics
2 answers:
Elina [12.6K]3 years ago
8 0
The correct answer is B
BartSMP [9]3 years ago
3 0

Answer:

B

Step-by-step explanation:

A is Standard Intercept Form

B is Point Slope Form

The rest are used for other problems I'm unsure of

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Double bubble/ triple 100 points !!!!!!
balu736 [363]

Answer:

see below

Step-by-step explanation:

We need to find the diameter of the square

We can find this using the Pythagorean theorem

a^2+b^2 = c^2  where the legs are 7 and 7 and the diameter is c

7^2 +7^2 = c^2

49+49 = c^2

98 = c^2

Taking the square root of each side

sqrt(98) = sqrt(c^2)

9.899494937 = c

Since 9.9 is less than 11 which is the diameter of the circle it will never touch the circle.

Since the longest part of the square is less than the diameter of the circle, the square will fit  inside the circle without touching

3 0
3 years ago
Read 2 more answers
A single card is drawn from a standard 52 card deck.
Alecsey [184]

Answer:

43

Step-by-step explanation:

3 0
3 years ago
Which property states that for all real numbers, x, y and z, if x = y and y = z, then x = z ?
Leto [7]

Answer:

The transitive property of equality

Step-by-step explanation:

The transitive property states if a=b and b=c then a=c. If two things are equal and one of those two things is equal to another thing, then they all must be equal.


4 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
A serving of hot chocolate requires ¾ cup of milk. How many servings can Nina make with 7 ½ cups of milk? *
patriot [66]

Answer:

8 cups of hot chocolate

Step-by-step explanation:

6 0
3 years ago
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