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Ray Of Light [21]
3 years ago
5

A 0.100 M oxalic acid, HO2CCO2H, solution is titrated with 0.100 M KOH. Calculate the pH when 25.00 mL of oxalic acid solution i

s titrated with 35.00 mL of NaOH
Chemistry
1 answer:
____ [38]3 years ago
3 0

Answer:

pH = 4.09

Explanation:

molarity of oxalic acid in the solution

         = 0.1 x 25 / (25 + 35)

         = 0.0417 M

molarity of NaOH in the solution

          = 0.1 x 35 / (25 +35)

         = 0.0583 M

H2C2O4 + NaOH -------------------> NaHC2O4 + H2O

0.0417          0.0583                            0                0

0                      0.0166                         0.0417

now second acid -base titration  

NaHC2O4 + NaOH -------------------> Na2C2O4 + H2O

0.0417             0.0166                              0                0

0.0251                 0                                  0.0166         ---

now

pH = pKa2 + log [Na2C2O4 / NaHC2O4]

pH = 4.27 + log (0.0166 / 0.0251)

pH = 4.09

You might be interested in
How much H2O is produced when 20000 g of C2H2 burns completely? Answer in units of g.
IgorC [24]

Answer:

Explanation:

H  = 1

C = 12

O = 16

Acetylene, HC≡CH = 2+24 = 26

H2O = 2 + 16 = 18

In XS oxygen, one HC≡CH yields one H2O

26 g HC≡CH  ==> 18 g H2O

2000 g HC≡CH ==> 2000*18/26 g H2O =  1384.6154 g H2O

3 0
4 years ago
A cubic box with sides of 20.0 cm contains 2.00 × 1023 molecules of helium with a root-mean-square speed (thermal speed) of 200
Anarel [89]

Answer:

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

Explanation:

Side of the cubic box = s = 20.0 cm

Volume of the box ,V= s^3

V=(20.0 cm)^3=8000 cm^3=8\times 10^{-3} m^3

Root mean square speed of the of helium molecule : 200m/s

The formula used for root mean square speed is:

\mu=\sqrt{\frac{3kN_AT}{M}}

where,

= root mean square speed

k = Boltzmann’s constant = 1.38\times 10^{-23}J/K

T = temperature = 370 K

M = mass helium = 3.40\times 10^{-27}kg/mole

N_A = Avogadro’s number = 6.022\times 10^{23}mol^{-1}

T=\frac{\mu _{rms}^2\times M}{3kN_A}

Moles of helium gas = n

Number of helium molecules = N =2.00\times 10^{23}

N = N_A\times n

Ideal gas equation:

PV = nRT

Substitution of values of T and n from above :

PV=\frac{N}{N_A}\times R\times \frac{\mu _{rms}^2\times M}{3kN_A}

PV=\frac{N\times R\times \mu ^2\times M}{3k\times (N_A)^2}

R=k\times N_A

PV=\frac{N\times \mu ^2\times M}{3}

P=\frac{2.00\times 10^{23}\times (200 m/s)^2\times 3.40\times 10^{-27} kg/mol}{3\times 8\times 10^{-3} m^3}

P=1133.33 Pa =1.133 kPa

(1 Pa = 0.001 kPa)

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

3 0
3 years ago
In the reaction A+B --> C + D, what are the reactants? Answer Fast please!!!
ale4655 [162]

Answer:

C + D

Explanation:

C + D are the reactants because they are on the right side of the equation

(I hope this answer was quick enough!)

4 0
3 years ago
A sample of glucose (C6H1206) contains 0.75 moles of oxygen. How many moles of hydrogen does this sample contain?
Snowcat [4.5K]

Answer:

15molH

Explanation:

Hello,

In this case, given that one mole of glucose, contains six moles of oxygen (subscript), we can also see it contains twelve moles of hydrogen (subscript), therefore, the moles of hydrogen in the sample are computed by:

0.75molO*\frac{1molC_6H_{12}O_6}{6molO}*\frac{12molH}{1molC_6H_{12}O_6}\\  \\=1.5molH

Best regards.

6 0
3 years ago
How many moles of naoh are present in 29.0 ml of 0.290 m naoh?
Dovator [93]
29.0 mL in liters:

29.0 / 1000 => 0.029 L

n = M x V

n = 0.290 x 0.029

n = 0.00841 moles of NaOH

hope this helps!
7 0
3 years ago
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