Answer:
a) τ = 1.039*10⁻⁴N-m
b) The net torque acting on the loop is zero, but the loop continues to rotate in a counterclockwise direction.
Explanation:
A) Given
I = 0.5 A
B = 0.3 T
a = 4 cm = 0.04 m
b = 2 cm = 0.02 m
θ = 30°
The torque τ acting on a current-carrying loop of area A due to the interaction of the current I flowing through the loop with a magnetic field of magnitude B is given by
τ = I*B*A*Sin∅
where ∅ is the angle between the normal to the loop and the direction of the magnetic field.
The area A of a rectangular loop of wire with height 4.00 cm and horizontal sides 2.00 cm can be obtained as follows
Aloop = a*b ⇒ Aloop = 0.04 m*0.02 m = 8*10⁻⁴m²
Recalling that θ is the angle between the sides of length b and B and if we consider the normal to the loop, the angle ∅ between the normal and the magnetic field is given by
∅ = 90°-θ ⇒ ∅ = 90°-30° = 60°
Then, the torque will be
τ = (0.5 A)*(0.3 T)*(8*10⁻⁴m²)*Sin60° = 1.039*10⁻⁴N-m
b) We have to get the net torque τ about the vertical axis of the current loop due to the interaction of the current with the magnetic field.
The angle ∅ between the normal to the loop and the magnetic field when the horizontal sides of the loop of length b are perpendicular to B is
∅ = 0°
Then
τ = (0.5 A)*(0.3 T)*(8*10⁻⁴m²)*Sin 0° = 0 N-m
We can say that the net torque acting on the loop is zero, but the loop continues to rotate in a counterclockwise direction.
Yes, C is correct. It self explains itself as we know light travels through a vacuum ( doesn't need a medium) and light is a type of electromagnetic wave.
Answer:
(a) 0.014 A
(b) 2 V
Explanation:
(a) Applying
V = IR'...................... Equation 1
Where V = Voltge, I = current, R = total resistance.
make I the subject of the equation
I = V/R'................... Equation 2
From the question,
Given: V = 12 V, R' = (122+232+500) ohms (The resistance are connected in series) = 854 ohms
Substitute these values into equation 2
I = 12/854
I = 0.014 A
(b) Applying
V' = V(R₁)/(R₁+R₂+R₃)...................... Equation 3
Where V' = Voltage across the 100 ohms resistor.
From the question,
V = 12V, R₁ = 100 ohm, R₂ = 200 ohm, R₃ = 300 ohm.
Substitute these values into equation 3
V' = (12×100)/(100+200+300)
V' = 1200/600
V' = 2 V
Answer:
1. direct current 2. induction 3. conduction
Explanation:
When we walk barefoot on a carpet there is friction between the carpet surface and the lower surface of the feet which results in the exchange of charges between the two surfaces. During this course the carpet loses electron to the surface of the foot. Now, the charge on the carpet is static because it is an insulator but a human body being a good conductor of electricity has mobility of the charges.(3)
These mobile charges on the surface of a human body spread and look for a path of dissipation to a reservoir. When we bring our hand near a metal it induces an opposite charge near the surface of the metal,(2) this happens within a fraction of seconds. Now there is a positive charge on the nearest point on the metal and the negative charge on its farthest end is induced according to the conservation of charges.
As soon as the hand touches the metal (1)there is a transfer of charge from our body to the metal generating a very small shock. This happens only if we continue to stand on an insulated surface due to which the charge doesn't gets transferred to the ground.
Velocity:
60 meters/ 5 seconds= 12 meters/second
Velocity=12meters/second
(60 meters divided by 5 seconds equals 12 meters per second)
Hope this helps!
