Question

Air in a thundercloud expands as it rises. If its initial temperature is 292 K and no energy is lost by thermal conduction on expansion, what is its temperature when the initial volume has tripled

Answer 1

Answer:

Explanation:

It is a case of adiabatic expansion .

$T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}$

T₁ , T₂ are initial and final temperature , V₁ and V₂ are initial and final volume.

Given ,

V₂ = 3 V₁ and T₁ = 292 . γ for air is 1.4 .

$( 3 )^{\gamma-1}= \frac{292}{ T_2}$

$( 3 )^{1.4-1}= \frac{292}{ T_2}$

1.552 = 292 / T₂

T₂ = 188 K .