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Alex73 [517]
2 years ago
7

Air in a thundercloud expands as it rises. If its initial temperature is 292 K and no energy is lost by thermal conduction on ex

pansion, what is its temperature when the initial volume has tripled
Physics
1 answer:
tiny-mole [99]2 years ago
3 0

Answer:

Explanation:

It is a case of adiabatic expansion .

T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}

T₁ , T₂ are initial and final temperature , V₁ and V₂ are initial and final volume.

Given ,

V₂ = 3 V₁ and T₁ = 292 . γ for air is 1.4 .

( 3 )^{\gamma-1}= \frac{292}{ T_2}

( 3 )^{1.4-1}= \frac{292}{ T_2}

1.552 = 292 / T₂

T₂ = 188 K .

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Answer:

f_{fr}=1590.85 N

Explanation:

Here the total force at the horizontal components will be equal to the centripetal force on the car. So we will have:

f_{fr}cos(25)+Nsin(25)=m\frac{v^{2}}{r} (1)

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Now, the sum of forces at the vertical direction is equal to 0.

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Let's combine (1) and (2) to find f(fr)

f_{fr}=\frac{(mv^{2}/r)-mgtan(25)}{cos(25)+tan(25)sin(25)}

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I hope it helps you!

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When the biker is at the top of the ramp, he has a speed of 10 m/s at
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Answer:

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The amount of gravitational potential energy acquired by the rock is equal to:
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