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GenaCL600 [577]
3 years ago
9

A 600-N box is pushed up a ramp that is 2 meters high and 5 meters long. The person exerts a force of 300-N. What is the efficie

ncy of the ramp?
Physics
1 answer:
AfilCa [17]3 years ago
6 0
From information given, there are two forces in action, the vertical and the horizontal. We first need to calculate separately work done by these two forces, then determine the efficiency. Work = Force × distance work(a) → 600N × 2m = 1,200 Nm work(b) → 300N × 5m = 1,500 Nm Efficiency = work(a) / work (b) × 100 Efficiency = 1200 / 1500 × 100 Efficiency = 0.8 × 100 Efficiency = 80% Therefore the efficiency of the ramp is 80%
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A child has an ear canal that is 1.3 cm long. At what sound frequencies in the audible range will the child have increased heari
ElenaW [278]

Answer:

The answer to this is

6600 Hz to 19,800 Hz

Explanation:

The shape of the human ear is analogous to a closed ended pipe hence

we have λ = 4L or wavelength = 4 * length of the child ear

The frequency  c/λ  where c = speed of sound = 343 m/s

hence the child's audible range is multiples of 343/(4*0.13) =6600Hz

or 13200 Hz or 19,800 Hz

The generally quoted range of human hearing is 20 Hz to 20 kHz

7 0
3 years ago
Which of the following is used to measure weight? Newtons Liters Kilograms Meters
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Newton’s is used to measure force.
Meters measures distance. Liters measures liquid. Kilograms measures mass & weight.

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6 0
3 years ago
Adam and kevin are roommates. Adam can clean their apartment in 45 minutes. Kevin can clean it in 60 minutes. Rounded to the nea
Karo-lina-s [1.5K]
If you add both numbers together it makes 105 but we’re talking time so it’ll be an hour and 45 minutes for them to clean their apartment.
5 0
3 years ago
Changes in the forms of energy are called
Dima020 [189]
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5 0
3 years ago
The place kicker on a football team kicks a ball from ground level with an initial speed of 5.80 m/s at an angle of 17.0° above
Likurg_2 [28]

Answer:

0.34 s

Explanation:

Given that,

Initial speed of a ball, u = 5.8 m/s

It is kicked at an angle of 17.0° above the horizontal.

The vertical component of velocity will be,

u_y=u\sin\theta\\\\=5.8\times \sin 17\\\\=1.69\ m/s

Let it takes t time in the air before it lands on the ground again. It can calculated as :

t=\dfrac{2u_y}{g}\\\\t=\dfrac{2\times 1.69}{9.8}\\\\t=0.34\ s

So, it will take 0.34 seconds.

8 0
3 years ago
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