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Oxana [17]
3 years ago
6

Which of the following is a correct statement about the endocrine system?

Biology
1 answer:
Gnesinka [82]3 years ago
5 0
<h3><u>Answer;</u></h3>

The adrenal glands sit on top of the kidneys and release adrenaline, which affects heart rate.

<h3><u>Explanation;</u></h3>
  • Adrenal glands are located at the top of each kidney. They produce hormones that help the body control blood sugar, burn protein and fat, react to stressors like a major illness or injury, and regulate blood pressure.
  • The Adrenal glands are made up of two regions; the adrenal cortex and the adrenal medulla. <em><u>The adrenal medulla produces hormones adrenaline also epinephrine and noradrenaline also norepinephrine. </u></em>
  • <em><u>Hormone adrenaline rapidly responds to stress by increasing your heart rate and rushing blood to the muscles and brain.</u></em>

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Describe how the structures of proteins differ from the structures of carbohydrates
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Answer:

Both are considered macromolecules. I'll explain below

Explanation:

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5 0
3 years ago
Assume that you have 1 mL of a solution of amylase (an enzyme) at a concentration of 15 mg protein/mL. Calculate the volume of d
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Answer:

42,5 mL

Explanation:

We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.

DF=\frac{Vi}{Vf}

<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>

The first step is to have the same measurment unit so we need to convert 345 µg to mg.

we know that 1 µg equals 0,001 g, hence:

345 µg = 0,345 mg

now the final volume is 0,345 mg  protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula

DF= \frac{15mg protein/mL}{0.345mg protein/mL}

DF= 43,5 mg protein/ mL

Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL

43,5mL-1,0mL = 42,5 mL

So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)

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