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3 years ago

How can you compare ratios to solve a problem?

Mathematics

2 answers:

vlabodo [156]3 years ago

8 0

Answer:

Identify the known ratio and the unknown ratio.

Set up the proportion.

Cross-multiply and solve.

Check the answer by plugging the result into the unknown ratio.

Step-by-step explanation:

Sindrei [870]3 years ago

6 0

“To use proportions to solve ratio word problems, we need to follow these steps:
Identify the known ratio and the unknown ratio.
Set up the proportion.
Cross-multiply and solve.
Check the answer by plugging the result into the unknown ratio.”
I hope this helps.

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Translate and solve: eight more than the product of three and a number is -13

Murrr4er [49]

Ok, so let’s take the given phrase.
Eight more than the product of 3 and a number is -13. A translation to numbers looks like this:
3x + 8 = -13
Now, let’s solve for x. We can start the process by subtracting 8 from both sides.
3x = -21
now, we will divide each side by 3 to isolate the variable, thus solving for x.
x = -7

6 0

3 years ago

Cyclists and runners are surveyed about their preferred method for replacing carbohydrates during a long race. The results of th

Novay_Z [31]

Answer:

no its not correct

Step-by-step explanation:

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3 years ago

Read 2 more answers

The area of a square ice rink is 400 yd.². What is the perimeter of the rink in yards

MakcuM [25]

Answer:

80 yd^2

Step-by-step explanation:

Since the formula for squares is s^2, we can use this to set up an equation, which is

s^2=400

If we square root this, we get

s=20

The perimeter formula for a square is 4s, so if we plug in, we end up with 80 yd^2

8 0

3 years ago

What are compatible numbers?

castortr0y [4]

Compatible numbers are numbers that are close in value to the actual numbers and easy to add, subtract, multiply, or divide mentally. They are useful in estimating the sum, difference, product, or quotient.

7 0

3 years ago

Solve the system of equations by graphing: 2x + 3y = 2 6x + 18y = 9

cluponka [151]

The answer is A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
Answer: {x = 1/2, y = 1/3

7 0

2 years ago