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3 years ago

Find an ordered pair (x,y) that is a solution to the equation.

Mathematics

2 answers:

vesna_86 [32]3 years ago

6 0

(5,-5) is your answer.

artcher [175]3 years ago

4 0

there are 3 possible solutions

(0,-5)

(1,0)

(2,2)

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The points (4, 1) and (x, -6) lie on the same line. If the slope of the line is 1 what is the value of x?

Nana76 [90]

Answer:

The value of x is -3

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of a line that passes through points (x1 , y1) and (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

* Lets solve the problem

∵ The points (4 , 1) and (x , -6) lie on the same line

∵ The slope of the line is 1

- Let the point (4 , 1) is (x1 , y1) and the point (x , -6) ix (x2 , y2)

∵ x1 = 4 , x2 = x and y1 = 1 , y2 = -6

∴ $m=\frac{x-4}{-6-1}$

∴ $m=\frac{x-4}{-7}$

∵ The slope of the line is m = 1

∴ $\frac{x-4}{-7}=1$

- By using cross multiplication

∴ x - 4 = -7 ⇒ add 4 to both sides

∴ x = -3

* The value of x is -3

4 0

4 years ago

Find the value of z such that 0.11 of the area lies to the right of z. Round your answer to two decimal places.

Art [367]

Answer:

1.23?

Step-by-step explanation:

6 0

3 years ago

Find the orthogonal complement W⊥ of W and give a basis for W⊥. W = x y z : x = 1 2 t, y = − 1 2 t, z = 6t.

igor_vitrenko [27]

Answer:

W⊥= (a, b, c)

a = v - (1/2)w

b = v

c = w

Basis for W⊥ = <(1,1,0),(-1/2,0,1)>

Step-by-step explanation:

The orthogonal complement of W is the set of vectors (a,b,c) that satisfy:

(x,y,z)·(a,b,c) = 0

ax + by + cz = 0

So, taking into account that x=12t, y=-12t and z=6t, the equation above is equal to:

12ta + -12tb + 6tc = 0

12a - 12b + 6c = 0

Then, if we made b=v and c=w and solve for a, we get:

12a - 12v + 6w = 0

a = (12v - 6w)/12

a = v - (1/2)w

Therefore, the orthogonal complement W⊥ of W has the form:

W⊥ = (a,b,c) = (v - (1/2)w, v, w)

On the other hand, we can write W⊥ as:

W⊥ = (v - (1/2)w, v, w)

W⊥ = (v,v,0) + ((-1/2)w,0,w)

W⊥ = v(1,1,0) + w(-1/2,0,1)

That means that we can write any vector of W⊥ as a linear combinations of the vectors (1,1,0) and (-1/2,0,1), so they are a basis for W⊥

7 0

4 years ago

The function f(x)= 3(1.4)' gives the length (in inches) of an image after being enlarged by 10% x times.

kondaur [170]

Answer:

3.99 inches

Step-by-step explanation:

The correct question is

The function f(x) = 3(1.1)^x gives the length (in inches) of an image after being enlarged by 10% x times.

What is the length of the image after it has been enlarged 3 times? Round your answer to the nearest hundredth

we have

$f(x)=3(1.1)^x$

This is a exponential growth function

where

f(x) represent the length (in inches) of an image

x is the number of times the image is enlarged

For x=3

substitute in the exponential equation

$f(x)=3(1.1)^3=3.99\ in$

4 0

3 years ago

What are the coordinates <img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%7Bx%20-%203%7D%20" id="TexFormula1" title="y

SashulF [63]

Answer: its A or b but i think A

Step-by-step explanation:

3 0

3 years ago