Answer:
865.08 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 243 m/s
Height (h) of the cliff = 62 m
Horizontal distance (s) =?
Next, we shall determine the time taken for the cannon to get to the ground. This can be obtained as follow:
Height (h) of the cliff = 62 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
62 = ½ × 9.8 × t²
62 = 4.9 × t²
Divide both side by 4.9
t² = 62/4.9
Take the square root of both side.
t = √(62/4.9)
t = 3.56 s
Finally, we shall determine the horizontal distance travelled by the cannon ball as shown below:
Initial velocity (u) = 243 m/s
Time (t) = 3.56 s
Horizontal distance (s) =?
s = ut
s = 243 × 3.56 s
s = 865.08 m
Thus, the cannon ball will impact the ground 865.08 m from the base of the cliff.
The bending of a wave as it crosses a boundary between 2 mediums at an angle is called refraction.
Answer:
C. 5.35 × 10^-5
Explanation:
5.35 × 0.00001 = 0.0000535
Hope this helped!
Answer:
Explanation:
Given
Halley's closest distance from sun is 
Greatest distance is 
Comet's speed at closest approach is 
As there is no external torque so angular momentum of comet about the sun is conserved
where 
This can be written as 
Therefore
