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soldi70 [24.7K]
2 years ago
8

During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.146 kg baseball crashing through the pane

of a second-floor window in a nearby building. The ball strikes the glass at 15.3 m/s , shatters the glass as it passes through, and leaves the window at 10.7 m/s with no change of direction. What is the direction of the impulse that the glass imparts to the baseball?
Calculate the magnitude of this impulse (a positive number).

The ball is in contact with the glass for 0.0106 s as it passes through. Find the magnitude of the average force of the glass on the ball (a positive number).
Physics
1 answer:
Nonamiya [84]2 years ago
6 0

Answer:

Impulse, |J| = 0.6716 kg-m/s

Force, F = 63.35 N

Explanation:

It is given that,

Mass of the baseball, m = 0.146 kg

Initial speed of the ball, u = 15.3 m/s

Final speed of the ball, v = 10.7 m/s

To find,

(a) The magnitude of this impulse.

(b) The magnitude of the average force of the glass on the ball.

Solution,

(a) Impulse of an object is equal to the change in its momentum. It is given by :

J=m(v-u)

J=0.146\ kg(10.7-15.3)\ m/s

J = -0.6716 kg-m/s

or

|J| = 0.6716 kg-m/s

(b) Another definition of impulse is given by the product of force and time of contact.

t = 0.0106 s

J=F\times \Delta t

F=\dfrac{J}{\Delta t}

F=\dfrac{0.6716\ kg-m/s}{0.0106\ s}

F = 63.35 N

Hence, this is the required solution.

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When light shines through atomic hydrogen gas, it is seen that the gas absorbs light readily at a wavelength of 91.63 nm. What i
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Answer:

D) 21

Explanation:

When gas absorbs light , electron at lower level jumps to higher level .

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Here energy absorbed is equivalent to wavelength of 91.63 nm

In terms of its energy in eV , its energy content is eual to

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Electron is lying in lowest or first level ie n = 1.

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Energy of n th level = - 13.6 / n². Let in this level electron has been excited

Difference of energy

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13.6 / n² = 13.6 - 13.57 = .03

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4 0
3 years ago
If the angle of incidence of a light source to a shiny surface is 30 degrees, what will the angle
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Find the energy in Joules required to lift a 55.0 Megagram object a distance of 500 cm.
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Energy to lift something =

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BUT ...

This simple formula only works if you use the right units.

Mass . . . kilograms
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Height . . . meters

For this question . . .

Mass = 55 megagram = 5.5 x 10⁷ grams = 5.5 x 10⁴ kilograms

Gravity (on Earth) = 9.8 m/second²

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So we have ...

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7 0
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hammer [34]

Answer:

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The answer is false.

Explanation:

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