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Tomtit [17]
3 years ago
6

Bill and Karen go to the ice-skating rink. Bill has twice the mass of Karen. While they are standing still and talking, suddenly

Bill pushes Karen backward. What can you say about the forces between Bill and Karen?
Physics
1 answer:
Oksana_A [137]3 years ago
3 0

Answer:

forces acting on the two will be equal and opposite in  nature according to Newton's third law of motion.

Explanation:

Given:

mass of Karen, m (let)

then, mass of Bill, 2m

When they are standing near one another and suddenly Bill pushes Karen then this can be treated as elastic collision and the conservation of momentum applies as:

Sum of final and initial momentum of the system is zero.

m.v_k-2m.v_b=0

2v_b=-v_k

v_b=-\frac{v_k}{2}

But the forces acting on the two will be equal and opposite in  nature according to Newton's third law of motion.

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ZanzabumX [31]

Answer:

Part a)

v_2 = \frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})}

Part b)

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Explanation:

Since the ball and rod is an isolated system and there is no external force on it so by momentum conservation we will have

Mv_o = M v_1 + m v_2

here we also use angular momentum conservation

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M v_o d = M v_1 d + \beta mL^2 \omega

also we know that the collision is elastic collision so we have

v_o = (v_2 + d\omega) - v_1

so we have

\omega = \frac{v_o + v_1 - v_2}{d}

also we know

M v_o d - M v_1 d = \beta mL^2(\frac{v_o + v_1 - v_2}{d})

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v_1 = v_o - \frac{m}{M}v_2

so we have

M v_o d - M(v_o - \frac{m}{M}v_2)d = \beta mL^2(\frac{v_o + v_o - \frac{m}{M}v_2 - v_2}{d})

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now we have

(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})v_2 = \frac{2\beta mL^2v_o}{d}

v_2 = \frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})}

Part b)

Now we know that speed of the ball after collision is given as

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so it is given as

v_1 = v_0 - \frac{m}{M}(\frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})})

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Answer:

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Explanation:

Recall that the y-component comes associated with the sin(18.4) through the following trigonometric relationship:

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Answer:

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