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Tomtit [17]
3 years ago
6

Bill and Karen go to the ice-skating rink. Bill has twice the mass of Karen. While they are standing still and talking, suddenly

Bill pushes Karen backward. What can you say about the forces between Bill and Karen?
Physics
1 answer:
Oksana_A [137]3 years ago
3 0

Answer:

forces acting on the two will be equal and opposite in  nature according to Newton's third law of motion.

Explanation:

Given:

mass of Karen, m (let)

then, mass of Bill, 2m

When they are standing near one another and suddenly Bill pushes Karen then this can be treated as elastic collision and the conservation of momentum applies as:

Sum of final and initial momentum of the system is zero.

m.v_k-2m.v_b=0

2v_b=-v_k

v_b=-\frac{v_k}{2}

But the forces acting on the two will be equal and opposite in  nature according to Newton's third law of motion.

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Answer:

Intensity of the light (first polarizer) (I₁) = 425 W/m²

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

Explanation:

Given:

Unpolarized light of intensity (I₀) = 950 W/m²

θ = 65°

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b. Intensity of the light (second polarizer)

Computation:

a. Intensity of the light (first polarizer)

Intensity of the light (first polarizer) (I₁) = I₀ / 2

Intensity of the light (first polarizer) (I₁) = 950 / 2

Intensity of the light (first polarizer) (I₁) = 425 W/m²

b. Intensity of the light (second polarizer)

Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

Intensity of the light (second polarizer) (I₂) = (425)(0.1786)

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How to derive the fourth equation of motion?
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\qquad\qquad\huge\underline{{\sf Answer}}♨

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\qquad \sf  \dashrightarrow \:m_1s_1

Heat capacity of body 2 :

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it's given that, the the head capacities of both the objects are equal. I.e

\qquad \sf  \dashrightarrow \:m_1s_1 = m_2s_2

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\qquad \sf  \dashrightarrow \: s' =  \dfrac{2s_1s_2}{s_1 + s_2}

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