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3 years ago

Write the equation of a line that contains (2,−2) and perpendicular to another line with slope −1.

Mathematics

2 answers:

Mila [183]3 years ago

6 0

Answer:

Y= x -4 is the correct answer

Reika [66]3 years ago

3 0

Answer:

y = x - 4

Step-by-step explanation:

Perpendicular slope = 1

y + 2 = 1 (x - 2)

y + 2 = x - 2

y = x - 4

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on the stock exchange, 100 shares of pizzazz corp. stock are selling $425. how many shares can be purchased for $1000?

Natali5045456 [20]

Answer:

235.29 shares can be purchased for $1000.

Step-by-step explanation:

On the stock exchange, 100 shares of pizzazz corp. stock are selling $425

We have to determine how many shares can be purchased for $1000?

The price of 100 shares = $425

The price of 1 share = 425/100 = $4.25

Now, It is very easy to calculate the number of shares can be purchased for $1000.

All you have to do is to divide by 1000 by 4.25.

i.e. 1000/4.25 = 235.29 shares

Therefore, 235.29 shares can be purchased for $1000.

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4 years ago

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

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2 years ago

How many grams are in 2000mg

Aleonysh [2.5K]

Answer:

2g :)

Step-by-step explanation:

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4 years ago

Read 2 more answers

Can someone help me solve for x+y=3 and x-y=1?

DENIUS [597]

$\underline{+\left\{\begin{array}{ccc}x+y=3\\x-y=1\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\\\.\ \ \ \ 2x=4\ \ \ \ |:2\\.\ \ \ \ x=2\\\\\text{put the value of x to the first equation}\\\\2+y=3\ \ \ \ |-2\\\\y=1\\\\Answer:\ x=2,\ y=1\to(2,\ 1)$

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