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sveticcg [70]
3 years ago
15

CAN SOMEONE PLEASE HELP ME I REALLY NEED IT, THANK YOU!!!

Mathematics
1 answer:
Darya [45]3 years ago
8 0

Answer:

the volume of the square pyramid is 750 cm³

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How do I solve 3x-5>0 ? Can someone explain please​
neonofarm [45]

Answer:

Find my Answer attached.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Resolve into factors. p4+7p2q2+16q4​
uranmaximum [27]

Step-by-step explanation:

p⁴+8p²q²+16q⁴

(p²)²+2×p²×4q²+(4q²)²

We know that,

  • (a+b)²=a²+2ab+b²

Therefore,

  • (p²)²+2×p²×4q²+(4q²)²
  • (p²+4q²)²
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7 0
3 years ago
Help me please just say which one?
lesantik [10]
C. i have only seen this method on checks

7 0
3 years ago
In △ABC,c=9, m∠B=65°, and a=105. Find b.
mart [117]

Answer:

  b ≈ 101.52

Step-by-step explanation:

Given two sides and the angle between, the Law of Cosines is useful.

  b^2 = a^2 +c^2 -2ac·cos(B)

  b^2 = 105^2 +9^2 -2·105·9·cos(65°) ≈ 10307.251

  b ≈ √10307.251

  b ≈ 101.52

7 0
3 years ago
Write the expression in simplest form.<br> ( 4 = + 3) – 2(- \ - - })= 0
Dimas [21]

Answer:

3^x=9^{x+5}

Step-by-step explanation:

3^x=9^{x+5}

x^2-x-6=0

x^4-5x^2+4=0

\sqrt{x-1}-x=-7

\left|3x+1\right|=4

\log _2\left(x+1\right)=\log _3\left(27\right)

3^x=9^{x+5}

If request to solve;

\mathrm{Convert\:}9^{x+5}\mathrm{\:to\:base\:}3

9^{x+5}=\left(3^2\right)^{x+5}

\mathrm{Solve\:}\:x=2\left(x+5\right):\quad x=-10

6 0
3 years ago
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