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koban [17]
3 years ago
8

What is 25.4067 rounded to the nearest hundredth ?

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0

Answer:your answer is 25.41

Step-by-step explanation:

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Number 6:
ivolga24 [154]

The answer is X=5 and Y =-2

View the picture to see step by step solution

8 0
3 years ago
Whats is the solution for 4х + 8 = 3х + 14​
cestrela7 [59]

Answer:

4x+8=3x+14

4x-3x=14-8

x=6

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3 years ago
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A triangle has side lengths of 20 cm, 99 cm, and 108 cm. Classify it as acute, obtuse, or right.
Tasya [4]
This doesn't make sense, as a triangle much equal 180, so it cannot have two angles bigger than 90, because this would mean it cannot be acute. A right triangle has one angle that is 90, obtuse as one that is bigger than 90 and two that are less, and an acute has three angles less than 90. Maybe there's a typo here? 
6 0
4 years ago
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If you borrow $100 for 3 years at a annual interest rate 9% how much will you pay altogether ?
katrin [286]

Answer:

$109

Step-by-step explanation:

<u>Formulas</u>

interest = (principal amount)(rate)(time)

<em>interest = (100)(0.09)(3) = $27</em>

total = principal amount + interest

<em>total = 100 + 9 = $127</em>

5 0
3 years ago
A local animal rescue organization receives an average of 0.55 rescue calls per hour. Use the Poisson distribution to find the p
andreyandreev [35.5K]

Answer:

B) 0.894

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A local animal rescue organization receives an average of 0.55 rescue calls per hour.

This means that \mu = 0.55

Probability that during a randomly selected hour, the organization will receive fewer than two calls.

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.55}*(0.55)^{0}}{(0)!} = 0.577

P(X = 1) = \frac{e^{-0.55}*(0.55)^{1}}{(1)!} = 0.317

P(X < 2) = P(X = 0) + P(X = 1) = 0.577 + 0.317 = 0.894

5 0
4 years ago
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