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Rom4ik [11]
3 years ago
14

When 26.62 miles of FeS2 reacts with 5.44 miles of O2 how many miles of SO2 are formed

Chemistry
1 answer:
Mademuasel [1]3 years ago
6 0
4 parts of FeS2 reacts with 11 parts of O2
so 26,62 moles of FeS2 would need 26,62/4 *11 = 73,2 moles of O2

So only 5,44 /11 *4 = 1,98 moles of FeS2 reacts with 5,44 moles of O2, O2 is the limiting
reactant
This means FeS2 is the reactant in excess and 26,62 - 5,44 = 21,18 moles of FeS2 are left over
and 1,98 * 8/4 = 3,96 moles of SO2 are formed
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Answer: There are 2.032 \times 10^{25} molecules S_{2} gas are in 756.2 L.

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It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of  moles present in 756.2 L are calculated as follows.

Mole = \frac{Volume}{22.4 L}\\= \frac{756.2 L}{22.4 L}\\= 33.76 mol

According to mole concept, 1 mole of every substance contains 6.022 \times 10^{23} molecules.

Therefore, molecules of S present in 33.76 moles are calculated as follows.

1 mol = 6.022 \times 10^{23}\\33.76 mol = 33.76 \times 6.022 \times 10^{23}\\= 2.032 \times 10^{25}

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