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Rom4ik [11]
3 years ago
14

When 26.62 miles of FeS2 reacts with 5.44 miles of O2 how many miles of SO2 are formed

Chemistry
1 answer:
Mademuasel [1]3 years ago
6 0
4 parts of FeS2 reacts with 11 parts of O2
so 26,62 moles of FeS2 would need 26,62/4 *11 = 73,2 moles of O2

So only 5,44 /11 *4 = 1,98 moles of FeS2 reacts with 5,44 moles of O2, O2 is the limiting
reactant
This means FeS2 is the reactant in excess and 26,62 - 5,44 = 21,18 moles of FeS2 are left over
and 1,98 * 8/4 = 3,96 moles of SO2 are formed
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What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.
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Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

pH=pK_{a} + log(\frac{[Base]}{[Acid]})

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pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

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