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3 years ago

When 26.62 miles of FeS2 reacts with 5.44 miles of O2 how many miles of SO2 are formed

1 answer:

6 0

4 parts of FeS2 reacts with 11 parts of O2
so 26,62 moles of FeS2 would need 26,62/4 *11 = 73,2 moles of O2

So only 5,44 /11 *4 = 1,98 moles of FeS2 reacts with 5,44 moles of O2, O2 is the limiting
reactant
This means FeS2 is the reactant in excess and 26,62 - 5,44 = 21,18 moles of FeS2 are left over
and 1,98 * 8/4 = 3,96 moles of SO2 are formed

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Answer:

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Explanation:

Step 1: Write the balanced equation

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Step 2: Calculate the moles corresponding to 2.34 g of S₈

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Step 3: Calculate the moles of SF₄ produced from 9.12 × 10⁻³ mol of S₈

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