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Yakvenalex [24]
3 years ago
6

Plsssssssssssssss help​

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

<em>(D). (8, - 5) </em>

Step-by-step explanation:

Coordinates of a center of a circle (x - h)² + (y - k)² = r² is (h, k)

Coordinates of the midpoint are ( \frac{x_{1} +x_{2} }{2} , \frac{y_{1} +y_{2} }{2} )

(x² - 10x + 25) + (y² + 2y + 1) = 25

(x - 5)² + (y + 1)² = 5²

(5, - 1) are coordinates of the center of the circle and (5, - 1) is a midpoint of the segment connected (2, 3) and (x, y)

5 = (2 + x) / 2 ⇒ x = 8

- 1 = (3 + y) / 2 ⇒ y = - 5

<em>(D). (8, - 5)</em>

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We know that :

Ф  Product of the slopes of two lines perpendicular to each other should be equal to -1

Let the slope of the line perpendicular to given line be : M

Given equation of the line : y = -1/2x + 4

This line is in the form : y = mx + c, where m is the slope and c is the y intercept

Comparing with y = mx + c :

we can notice that slope of the given line is -1/2

⇒   M × -1/2 = -1

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⇒   M = 2

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(ED. 21) Analytic Geometry Unit Test..... #3 Which point is a solution of x2 + y2 &gt; 49 and y ≤ –x2 – 4?
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We want to find a solution of the system:

x^2 + y^2 > 49

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(x - a)^2 + (y - b)^2 = R^2

If we look at our first inequality, we can write it as:

x^2 + y^2 > 7^2

So the solutions of the first inequality are all the points that are outside (because the symbol used is >) of the circle of radius R = 7 centered in the origin.

From the other equation, we would get:

y ≤ –x^2 – 4

This is parabola, anything that is in the graph of the parabola or below will be a solution for this inequality.

Then the solutions of the system, are the ones that are in the region of solutions for both inequalities.

You can see the graph below, where both regions are graphed. The intersection of these regions is the region of the solutions for the system of inequalities:

by looking at the graph, we can see a lot of points that are solutions, like:

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