Answer:
45 meters
Step-by-step explanation:
If x represents the seconds after the launch, then the time of launch is when x=0 so you just need to solve for h(0)
h(0) = -5(1)(-9)
h(0) = 45
Answer:
X=2
Y=1/4*2
Y=1/2
Y=.5
Step-by-step explanation:
PROOF
2*2+2*.5=5
4+1=5
5=5
Answer:
2/3
Step-by-step explanation:
In the 5-minute interval between 7:00 and 7:05, a train to B is the first to arrive. In the 10-minute interval between 7:05 and 7:15, a train to A is the first to arrive. That is, in any 15-minute interval, the probability is 10/15 = 2/3 that a train to A is the first to arrive.
The 1-hour interval between 7 A.M. and 8 A.M. is an integer number of such intervals, so ...
2/3 of the time, he or she will go to destination A.
=(-4/5)^2 * -3/50
square -4/5 first; remember -4/5^2 is the same as -4/5 * -4/5
=(-4/5 * -4/5) * -3/50
multiply -4 numerators; multiply 5 denominators
=(-4 * -4)/(5 * 5) * -3/50
=16/25 * -3/50
multiply numerators 16 & -3; multiply denominators 25 & 50
=(16 * -3)/(25 * 50)
= -48/1250
simplify by 2
= -24/625 (or -0.0384)
ANSWER: -24/625 (or -0.0384)
Hope this helps! :)
The null hypothesis suggests that the two samples come from the same distribution(s), and the experimental hypothesis suggests that the two samples come from different distribution(s).
