Answer:x^3+13x^2+3
Step-by-step explanation:
(2x^3+11x^2+5)-(x^3-2x^2+2)
Clearing brackets
2x^3+11x^2+5-x^3+2x^2-2
Collect like terms
2x^3-x^3+11x^2+2x^2+5-2
x^3+13x^2+3
Answer:
The number is 492,875.
Step-by-step explanation:
Given:
A number that is = 
Place value of 4 = 
Place value is ten thousands.
We have to identify the number where the place value of 4 is 10 times of the given number.
Numbers given:
284,796 or 327,498 or 492,875 and 742,186.
Lets see the place value of 4 in each of the number.
⇒
-
place value of
is
. - Place value of 4 is thousands.
⇒
place value of
is
.- Place value of 4 is hundreds.
⇒
place value of
is
.- Place value of 4 is hundred thousands.
⇒
place value of
is
.- Place value of 4 is ten thousands.
Notes:
Ten thousands multiplied with ten is hundreds thousand.
⇒ 
So,
The number which has digit 4 as hundred thousands place values is 492,875.
The amount an investment of 16000 grows over 7 years is 16000*0.12 (i.e., 12% of 16000). So, the total amount after 7 years is 16000 + 16000*0.12, which is the same as writing 16000*1.12. Now, continue the same argument: the amount we now have 16000*1.12 grows after another 7 years to (16000*1.12)*1.12. Third 7-year period, again, (16000*1.12*1.12*)*1.12, and so on. As you can already see the number of periods shows up as the number of factors 1.12 multiplied here. A shorthand for writing that is to use the exponent, like this
.
Generalizing to n 7-year periods yields a formula:

I hope this helps you
B 90 clockwise rotation