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3 years ago

FOR BRAINLIEST! Does the time in the air depend on forward velocity? Explain why

1 answer:

5 0

The time in air is determined by the initial vertical velocity. This is because, the steeper the launch angle the larger the vertical velocity component, that causes the launch angle to increase the time in air.

I did Physics a while ago but I believe my answer is correct. (:

Hope this helps! (:

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The Problems: 1. Xavier starts at a position of 0 m and moves with an average speed of 0.50 m/s for 3.0 seconds. He normally mov

NemiM [27]

Answer:

(1). His final position is 1.5 m.

(2). The final position of the hedgehog is 3 m.

(3). The final position of the tortoise

(4). Her race time is 80 sec.

(5). It take to finish in 5 hr.

Explanation:

(1). Given that,

Initial position = 0 m

Average speed = 0.50 m/s

Time = 3.0 s

We need to calculate the final position

Using formula of average speed

$v_{av}=\dfrac{x_{f}+x_{i}}{t}$

Where, $x_{f}$ = final position

$x_{i}$ = Initial position

t = total time

Put the value into the formula

$0.50=\dfrac{x_{f}+0}{3.0}$

$x_{f}=0.50\times3.0$

$x_{f}=1.5\ m$

(2). Given that,

Initial position = 0 m

Average speed = 0.75 m/s

Time = 4.0 s

We need to calculate the final position

Using formula of average speed

$v_{av}=\dfrac{x_{f}+x_{i}}{t}$

Put the value into the formula

$0.75=\dfrac{x_{f}+0}{4.0}$

$x_{f}=0.75\times4.0$

$x_{f}=3\ m$

(3). Given that,

Average speed = 1.25 m/s

Time = 3.0 sec

Initial position = 1.0 m

We need to calculate the final position

Using formula of average speed

$v=\dfrac{x_{f}+x_{i}}{t}$

Put the value into the formula

$1.25=\dfrac{x_{f}+1.0}{3.0}$

$x_{f}=1.25\times3.0-1.0$

$x_{f}=2.75\ m$

(4). Given that,

Average speed = 1.25 m/s

Distance = 100 m

We need to calculate the time

Using formula of time

$t=\dfrac{d}{v}$

Put the value into the formula

$t=\dfrac{100}{1.25}$

$t=80 sec$

(5). Given that,

Average speed = 5 miles/hr

Suppose, distance = 25 miles

We need to calculate the time

Using formula of time

$t=\dfrac{d}{v}$

Put the value into the formula

$t=\dfrac{25}{5}$

$t=5\ hr$

Hence, (1). His final position is 1.5 m.

(2). The final position of the hedgehog is 3 m.

(3). The final position of the tortoise

(4). Her race time is 80 sec.

(5). It take to finish in 5 hr.

5 0

4 years ago

PLEASE HELP!

lora16 [44]

Answer:

3. Has no moons

2. One of the rocky planets

1. The moon has no atmosphere.

Explanation:

Mars moons [2]: Deimos, Phobos; Jupiter is considered a Jovian [Gas Giant] planet; our moon has a very thin atmosphere.

5 0

3 years ago

__________ is the term for a reaction where energy is released.

Ivenika [448]

Exothermic is the term for a reaction where energy is released.

4 0

3 years ago

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If you throw your annoying little sister down the stairs with a force of 60 N and she weighs 30 kg. What’s her acceleration rate

Fynjy0 [20]

Answer:

Her acceleration rate is death.

Explanation:

4 0

3 years ago

Read 2 more answers

If the radius of an object in circular motion is doubled, what change will occur in the centripetal force?

cestrela7 [59]

Answer:

The centripetal force will be 1/2 as big as it was. (option c)

Explanation:

Recall that centripetal force ( $F_c$ ) is defined as: $F_c=m\,* \frac{v^2}{r}$ where "v" is the tangential velocity of the object in circular motion, "r" is the radius of rotation and "m" is the object's mass.

So if we start with such formula with a given mass, radius, and tangential velocity, and then we move to a situation where everything stays the same except for the radius which doubles, then the new centripetal force ( $F'_c$ ) will be given by: $F'_c=m\,* \frac{v^2}{2r}$

and this is half (1/2) of the original force:

$F'_c=m\,* \frac{v^2}{2r}\\F'_c=m\,* \frac{v^2}{r}*\frac{1}{2} \\F'_c=F_c\,*\,\frac{1}{2}$

which is expressed by option "c" of the provided list.

8 0

3 years ago

Read 2 more answers