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Natalka [10]
4 years ago
12

Light refracts because

Physics
2 answers:
NeTakaya4 years ago
5 0

Answer:

it travels at a different refractive index.

Explanation:

for example when light travels into water, it slows down, causing it to continue to travel at a different or another angle or direction. hope this helped!

Lunna [17]4 years ago
5 0

Refraction of light occurs due to the different refractive indices of the medium in which the light travels.

<u>Explanation: </u>

The medium through which the light travels have different refractive indices, because of which the light rays crosses the boundary of the refractive indices. They are shifted from the travelling line according to the refractive index of the medium and hence, refraction is seen.

For example, air is medium with less refractive index as compared to glass, and therefore the light ray when enters into glass, travels slow and refracted from the actual path towards the normal of the ray.

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What observations of the martian surface led lowell to the conclusion that intelligent life forms existed on mars?
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3 0
2 years ago
As frequency increases, what happens to the tone (or pitch) of a sound? Which option is it?
icang [17]

Answer:

gets higher

Explanation:

There are videos that show the range of human hearing.  If you would play the video, you would notice that if the frequency increases, the pitch would also increase.

3 0
4 years ago
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Unbalanced. _______ and not equal.  in not sure about the 2nd choice from the info im looking at. the balanced version is 2NaOH<span> + </span><span>H2SO4</span><span> = </span><span>Na2SO4</span><span> + </span>2<span>H2O
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7 0
4 years ago
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A hockey puck moving at 0.4600 m/s collides with another puck that was at rest. The pucks have equal mass. The first puck is def
Sladkaya [172]

Answer:

Speed =0.283m/ s

Direction = 47.86°

Explanation:

Since it is a two dimensional momentum question with pucks having the same mass, we derive the momentum in xy plane

MU1 =MU2cos38 + MV2cos y ...x plane

0 = MU2sin38 - MV2sin y .....y plane

Where M= mass of puck, U1 = initial velocity of puck 1=0.46, U2 = final velocity of puck 1 =0.34, V2 = final velocity of puck 2, y= angular direction of puck2

Substitute into equation above

.46 = .34cos38 + V2cos y ...equ1

.34sin38 = V2sin y...equ2

.19=V2cos Y...x

.21=V2sin Y ...y

From x

V2 =0.19/cost

Sub V2 into y

0.21 = 0.19(Sin y/cos y)

1.1052 = tan y

y = 47.86°

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.19 = V2 cos 47.86°

V2=0.283m/s

7 0
3 years ago
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