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3 years ago

A car accelerates from a standstill to 60 km/hr in 10 seconds. what is the cars acceleration

Physics

1 answer:

Inessa [10]3 years ago

6 0

Answer:
I’m not sure but I think it’s 6
Hope that helps

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What happened to the weight of an object when it is taken from Earth to the Moon? why?<br>

Sholpan [36]

Answer:

the weight of the object decreases when it is taken from the Earth to the Moon

Explanation:

The weight of an object is defined as the product of the mass of the object with the acceleration due to gravity of the Planet.

$W =mg$

where,

W = weight of the object

m = mass of the object

g = acceleration due to gravity on the planet

The mass of an object remains constant everywhere in the universe. Therefore, the weight is directly proportional to the value of acceleration due to gravity.

The value of acceleration due to gravity on the Moon is lesser than its value on the Earth.

<u>Hence, the weight of the object decreases when it is taken from the Earth to the Moon </u>

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3 years ago

Convert 3.2 kilometers to feet?

Tanzania [10]

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Explanation:

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3 years ago

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If you were to push a pile of books across a table, in which location would this be the easiest?

kati45 [8]

same amount is the answer

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3 years ago

A saddle weighs 250 newtons. The mass of the saddle is __________ kilograms. Use g = 9.8 N/kg for gravity.

Irina18 [472]

Answer:

saddle weighs 250 newtons. The mass of the saddle is ____250/9.8 kg______ kilograms. Use g = 9.8 N/kg for gravity.

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2 years ago

Use the work-energy theorem to determine the force required to stop a 1000 kg car moving at a speed of 20.0 m/s if there is a di

Vlad1618 [11]

Answer:

4.44 kN in the opposite direction of acceleration.

Explanation:

Given that, the initial speed of the car is, $u=20m/s$

And the mass of the car is, $m=1000 kg$

The total distance covered by the car before stop, $s=45m$

And the final speed of the car is, $u=0m/s$

Now initial kinetic energy is,

$KE_{i}=\frac{1}{2}mu^{2}$

Substitute the value of u and m in the above equation, we get

$KE_{i}=\frac{1}{2}(1000kg)\times (20)^{2}\\KE_{i}=20000J$

Now final kinetic energy is,

$KE_{f}=\frac{1}{2}mv^{2}$

Substitute the value of v and m in the above equation, we get

$KE_{f}=\frac{1}{2}(1000kg)\times (0)^{2}\\KE_{i}=0J$

Now applying work energy theorem.

Work done= change in kinetic energy

Therefore,

$F.S=KE_{f}-KE_{i}\\F\times 45=(0-200000)J\\F=\frac{-200000J}{45}\\ F=-4444.44N\\F=-4.44kN$

Here, the force is negative because the force and acceleration in the opposite direction.

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3 years ago

A car accelerates from a standstill to 60 km/hr in 10 seconds. what is the cars acceleration ​

A car accelerates from a standstill to 60 km/hr in 10 seconds. what is the cars acceleration