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What sort of process converts the mechanized energy in the ocean into electricity?

allochka39001 [22]

I think it is the wave energy.
Wave energy also known as the ocean energy is the energy harnessed from the ocean or sea waves. It is a source of power that comes from the endless march of the waves as they roll into the shore then back out. Using wave energy is advantageous as they are environmental friendly as there are no harmful byproducts, and also the energy from waves can be taken directly into electricity-producing machinery and used to power generators.

5 0

3 years ago

Anna applies a force of 19.5 newtons to push a book placed on a table. If the normal force of the book is 51.7 newtons, what is

k0ka [10]

The formula is Force = coefficient of friction times the weight or normal force (in newtons). Plug the numbers in the formula. Do the simple division math. The coefficient of friction should be any number between 0 and 1. If your answer is smaller than 0 or greater than 1, go back and check your work. The answer for this question is C. 0.38

5 0

3 years ago

Read 2 more answers

Anyone know the answer to this question?

nikitadnepr [17]

- The integers 1,2,3,4,5,6,7,8,9 are always significant

- Zeros in between numbers are always significant

Explanation:

The rules to determine whether a digit is significant or not are the following:

- All the non-zero digits are significant: 1,2,3,4,5,6,7,8,9

- The zeros between two non-zero numbers are always significant

- The zeros before non-zero numbers on the left of the decimal point are never significant

- The zeros given after a non-zero number on the right of the decimal point are significant if they provide information about the precision of the measure

So now let's analyze the statements given:

- The integers 1,2,3,4,5,6,7,8,9 are always significant --> true

- All numbers to the right of the decimal point are always significant --> false. For instance, in 0.012, only 1 and 2 are significant.

- Zeros to the left of a decimal point and in a number greater than or equal to 10 are always significant --> false. For instance, in 7200, the two zeros are not significant.

- All zeros are significant numbers --> false, as we saw in the previous examples

- Zeros in between numbers are alwasy significant --> true

Learn more about significant figures here:

brainly.com/question/5028090

#LearnwithBrainly

4 0

3 years ago

A wheel with radius 36 cm is rotating at a rate of 19 rev/s.(a) What is the angular speed in radians per second? rad/s(b) In a t

Sedaia [141]

(a) 119.3 rad/s

The angular speed of the wheel is

$\omega= 19 rev/s$

we need to convert it into radiands per second. We know that

$1 rev = 2 \pi rad$

Therefore, we just need to multiply the angular speed of the wheel by this factor, to get the angular speed in rad/s:

$\omega = 19 rev/s \cdot (2\pi rad/rev))=119.3 rad/s$

(b) 596.5 rad

The angular displacement of the wheel in a time interval t is given by

$\theta= \omega t$

where

$\omega=119.3 rad$

and

t = 5 s is the time interval

Substituting numbers into the equation, we find

$\theta=(119.3 rad/s)(5 s)=596.5 rad$

(c) 127.3 rad/s

At t=10 s, the angular speed begins to increase with an angular acceleration of

$\alpha = 1.6 rad/s^2$

So the final angular speed will be given by

$\omega_f = \omega_i + \alpha \Delta t$

where

$\omega_i = 119.3 rad/s$ is the initial angular speed

$\alpha = 1.6 rad/s^2$ is the angular acceleration

$\Delta t = 15 s - 10 s = 5 s$ is the time interval

Solving the equation,

$\omega_f = (119.3 rad/s) + (1.6 rad/s^2)(5 s)=127.3 rad/s$

(d) 616.5 rad

The angle through which the wheel has rotated during this time interval is given by

$\theta = \omega_i \Delta t + \frac{1}{2} \alpha (\Delta t)^2$

Substituting the numbers into the equation, we find

$\theta = (119.3 rad/s)(5 s) + \frac{1}{2} (1.6 rad/s^2) (5 s)^2=616.5 rad$

(e) 222 m

The instantaneous speed of the center of the wheel is given by

$v_{CM} = \omega R$ (1)

where

$\omega$ is the average angular velocity of the wheel during the time t=10 s and t=15 s, and it is given by

$\omega=\frac{\omega_i + \omega_f}{2}=\frac{127.3 rad/s+119.3 rad/s}{2}=123.3 rad/s$

and

R = 36 cm = 0.36 m is the radius of the wheel

Substituting into (1),

$v_{CM}=(123.3 rad/s)(0.36 m)=44.4 m/s$

And so the displacement of the center of the wheel will be

$d=v_{CM} t = (44.4 m/s)(5 s)=222 m$

8 0

3 years ago

If a car change the velocity from 36M/S to 28M/S with an acceleration of -2.0 M/S then how much time does it take for the vehicl

leonid [27]

The time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.

<h3>How to calculate deceleration?</h3>

Deceleration is the amount by which a speed or velocity decreases (and so a scalar quantity or a vector quantity).

The deceleration of a body can be calculated using the following formula:

-a = (v - u)/t

Where;

-a = deceleration
v = final velocity
u = initial velocity
t = time in seconds

-2 = (28 - 36)/t

-2t = -8

t = 4s

Therefore, the time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.

Learn more about deceleration at: brainly.com/question/4403243

#SPJ1

6 0

2 years ago