Answer:
4.489 m/s
Explanation:
We are given;
Length of rod;L = 51.4 cm = 0.514 m
When the ball is at the top end, it's velocity will be zero and it's kinetic energy will be transformed to potential energy.
Thus; ½mv² = mgh
m will cancel out to give;
v² = 2gh
Where:
g is acceleration due to gravity = 9.8 m/s²
h is the maximum height of the ball which is equal to twice the length of the rod.
Thus, h = 2(0.514) = 1.028 m
v² = 2 × 9.8 × 1.028
v = √20.1488
v = 4.489 m/s
<h2>
Question
</h2>
A particle, mass 0.25 kg is at a position (<em>-7i + 7j + 5k</em>) m, has a velocity (<em>6i - j + 4k</em>) m/s, and is subject to a force (<em>-5i + 0j - k</em>) N. What is the magnitude of the torque on the particle about the origin?
<h2>
Answer:</h2>
47.94Nm
<h2>
Explanation:</h2>
The torque (τ) on a particle subject to a force (represented as force vector F) at a position (represented as position vector r) about the origin is given by the cross product of the position vector r for the point of application of a force and the force F. i.e
τ = r x F
Given:
r = (-7i + 7j + 5k) m
F = (-5i + 0j - k) N
| i j k |
r x F = | -7 7 5 |
| -5 0 -1 |
r x F = i(-7 - 0) - j(7+25) + k(0+35)
r x F = i(-7) - j(32) + k(35)
r x F = -7i - 32j + 35k
Therefore the torque τ = -7i - 32j + 35k
The magnitude of the torque is therefore;
|τ| =
|τ| =
|τ| =
|τ| = 47.94Nm
The magnitude of the torque on the particle about the origin is 47.94Nm
Answer:
The net force acting on the box is 2N to the left.
Explanation:
The net force acting that is on an object is the sum of all of the individual forces acting on it.
If two forces act on an object in opposite directions, the net force is the difference between the two forces. In this case, the net force is always greater than or equal to zero but less than either of the individual forces.
If two forces act on an object in the same direction, the net force is the sum of the two forces. In this case, the net force is always greater than either of the individual forces.
Here in the figure the two forces acting in opposite direction on the object.
The direction of the resultant force is same direction as the force with the larger magnitude
Thus the net force is 2N to the left
Example of surface events are erosion and weathering. Erosion is the carrying of a particle from one place to the other and weathering is the breaking down of particles. These processes help in rock formation because this allows physical changes (grouping together or breaking down) on a certain substance. Subsurface events are those which happened underground such as the flow of underground water which subsequently allow the deposition of minerals, etc.