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alina1380 [7]
3 years ago
15

Vertically polarized light with an intensity of 36.8 lux passes through a polarizer whose transmission axis is an angle of 51.0°

with the vertical. What is the intensity and direction of transmitted light? If the second polarizer whose transmission axis is an angle of 88.0° with the vertical is placed after first polarizer, what is the intensity of transmitted light?
Physics
1 answer:
Annette [7]3 years ago
5 0

Answer:

0.01774 lux

Explanation:

I_0 = Polarized light intensity = 36.8 lux

\theta = Angle

Through first filter

I_1=I_0cos^2\theta\\\Rightarrow I_1=36.8cos^2{51}\\\Rightarrow I_1=14.57\ lux

Through second filter

I_2=I_1cos^2\theta\\\Rightarrow I_2=14.57cos^2{88}\\\Rightarrow I_2=0.01774\ lux

intensity of transmitted light is 0.01774 lux

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3 years ago
A +2e charge is at the point (-1,0) mm in the x,y plane. A –e charge is at the point (0,1) mm. What is the electric field at the
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Answer:

Let I and j be the unit vector along x and y axis respectively.

Electric field at origin is given by

E= kq1/r1^2 i + kq2/r2^2j

= 9*10^9*1.6*10^-19*/10^-6*(2i+ j)

= (2.88i + 1.44j)*10^-3 N/C

Force on charge= qE= 3*10^-19*1.6*(2.88i +1. 44 j) *10^-3

F= (1.382 i + 0.691 j) *10^-21

 

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Explanation:

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2 years ago
Which statement is true about an atom and an element?
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7 0
3 years ago
A diagram of a closed circuit with a power source on the left labeled 120 V. There are 3 resistors in parallel, separate paths,
Zina [86]

1) The equivalent resistance is 2.73\Omega

2) The voltage in the circuit is 120 V

3) The total current in the circuit is 44.0 A

Explanation:

1)

Resistors are said to be in parallel when they have the same potential difference at their terminals.

The formula to calculate the equivalent resistance for three resistors in parallel is:

\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

where R_1, R_2, R_3 are the resistances of the three resistors.

In this problem, the resistance of each resistor is:

R_1 = 5.0 \Omega

R_2 = 10.0 \Omega

R_3 = 15.0 \Omega

Substituting,

\frac{1}{R_T}=\frac{1}{5}+\frac{1}{10}+\frac{1}{15}=\frac{11}{30}

So the equivalent resistance is

R_T = \frac{30}{11}=2.73 \Omega

2)

In this problem we are told that the three resistors are connected in parallel. This means that their terminals are connected to the same point of the circuit: therefore, this means that they also have the same potential difference across them.

Therefore, the voltage in each branch containing each resistor is the same, and it is equal to the voltage of the battery, which is

V=120 V

So, the voltage in the circuit is 120 V.

3)

The total current in the circuit can be found by using Ohm's law:

V=RI

where

V is the voltage

R is the equivalent resistance of the circuit

I is the current

In this circuit, we have:

V = 120 V

R=2.73\Omega

Re-arranging the equation for I, we find the current:

I=\frac{V}{R}=\frac{120}{2.73}=44.0 A

Learn more about current and potential difference:

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#LearnwithBrainly

4 0
3 years ago
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mamaluj [8]

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Explanation: Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

6 0
3 years ago
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