Sulphur
The missing element is sulphur
Here the compound is composed of element X and chlorine.
it is given,
XCl (6) ----> 6Cl
mass = 13.1%
it is X and Cl = 100%-13.10%
= 86.90%
chlorine = 86.90
X = 13.10
We assume 100g of sample
so according to the above solved data, in 100g of sample we have 86.90 g of chlorine.
now we split that chlorine into two moles of chlorine.
- Every mole of sale has 35.45 grams of sales. 2.451 moles of seal are mine after that.
- We are aware that cl is six times more than X. To find the moles of X, I must divide this number by six.
- we discover that we have 0.4086 moles of X when we divide this by six.
- We obtain those moles of X from 13.10 g of X.
- Given that Mueller masses grams per mole, I can compute the molar mass.
- 13.10 grams of X are contained in 0.4086 moles of X.
- Or, to put it another way, each remote has a molar mass of 32–06 grams.
- The element with this molar mass is sulfur, as I can see from the periodic table.
- Okay, so the element we're looking for in this situation is sulfur.
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Answer:
A
Explanation:
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Answer:
a) J = F t = 40 * .05 = 2 N-s
b) J = 2 N-s momentum changed by 2 N-s
c) Initial momentum appears to be zero
J = change in momentum = m v2 - m v1 = m v2 = 2 N-s
v2 = J / m = 2 / .057 = 35 m/s
d) if the impulse time was increased and the average force remained the same then the change in momentum would increase with a corresponding increase in velocity attained - note the increase in v2 in part c)
B. Move from their ground states up to excited states
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The minimum average speed it must have in the second half of the event in order to qualify is 414.7 km/h.
<h3>
What is average speed?</h3>
The average speed of an object is the ratio of total distance traveled by the object to the total time of motion of the object.
<h3>Total time taken by the car during the entire race</h3>
time = distance/average speed
time = (1.41 km) / (278 km/h)
time = 0.0051 hr
The car travels the first half of the race, d (¹/₂ x 1410 m) at 210 km/h;
d = 705 m = 0.705 km
t1 = 0.705/210
t1 = 0.0034 hr
<h3>time for the second half</h3>
t2 = 0.0051 - 0.0034 hr
t2 = 0.0017 hr
<h3>minimum average speed of the second half</h3>
v = d/t
v = 0.705 km / 0.0017 hr
v = 414.7 km/hr
Thus, the minimum average speed it must have in the second half of the event in order to qualify is 414.7 km/h.
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