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3 years ago

Explain how surface and subsurface events are integral parts of the rock cycle.

1 answer:

3 0

Example of surface events are erosion and weathering. Erosion is the carrying of a particle from one place to the other and weathering is the breaking down of particles. These processes help in rock formation because this allows physical changes (grouping together or breaking down) on a certain substance. Subsurface events are those which happened underground such as the flow of underground water which subsequently allow the deposition of minerals, etc.

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How many meters per second was it traveling

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3 years ago

A 2000 kg truck traveling north at 34 km/h turns east and accelerates to 58 km/h. (a) What is the change in the truck's kinetic

barxatty [35]

Explanation:

It is given that,

Mass of the truck, m = 2000 kg

Initial velocity of the truck, u = 34 km/h = 9.44 m/s

Final velocity of the truck, v = 58 km/h = 16.11 m/s

(a) Change in truck's kinetic energy, $\Delta E=\dfrac{1}{2}m(v^2-u^2)$

$\Delta E=\dfrac{1}{2}\times 2000\ kg\times (16.11^2-9.44^2)$

$\Delta E=170418.5\ J$

$\Delta E=1.7\times 10^5\ J$

(b) Change in momentum of the truck, $\Delta p=m(v-u)$

$\Delta p=2000\ kg\times (16.11-9.44)$

$\Delta p=13340\ kg-m/s$

Hence, this is the required solution.

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3 years ago

If a wave has speed of 235 m/s with a wavelength of 3 m, what is the frequency of the wave?

maria [59]

I think it’s 25 but I don’t know

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2 years ago

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Svetradugi [14.3K]

20.0M/S. IS THE HORIZONTAL VELOCITY OF THE BALL JUST BEFORE IT REACHES THE GROUND

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3 years ago

A vertical spring launcher is attached to the top of a block and a ball is placed in the launcher, as shown in the figure. While

kvasek [131]

For a vertical spring launcher is attached to the top of a block and a ball is placed in the launcher, the position of the ball will be behind the box

<h3>What will be the position of the ball relative to the spring launcher?</h3>

Generally, the equation for the conservation of momentum principle is mathematically given as

(M+m) V1 = M*V2

Therefore, with the ball moving forward we have that; the ball at top it wii be behind the box,