If there is no air resistance, the value would still be the same. So therefore, the answer is 39.7 N.
Supposing that there is an air resistance of 19.8 N.With a 19.8 N air resistance: ∑F = 39.7 N - 19.8 N = 19.9 N would be the net force. The important point here is that the force of gravity equivalent the weight of the object.
Explanation:
A person standing still for a long time feels tired because the force of gravity acts on our body and puts stress on our muscles. so our muscles need energy to do work and keep body balanced and help to stand upright.
Answer:
The magnitude of acceleration is 3 m/s^2.
Explanation:
The net force along North-South direction is 18-24=-6 N.
The net force along East-West direction is 16-16=0 N
The net magnitude of force is square root of (-6)^2+0^2 which is 6 N.
By Newton's Second law,
Force F=ma
Therefore acceleration a=F/m
a=6/2
a=3 m/s^2
Learn more about Newton's second law.
brainly.com/question/13447525
#SPJ10
Answer:
Angle of Refraction = 28.9 degrees
Explanation:
<u><em>We'll use Snell's law for this. It's mathematical form is:</em></u>
=> ![n_1* sin(\alpha _1)=n_2 * sin(\alpha _2)](https://tex.z-dn.net/?f=n_1%2A%20sin%28%5Calpha%20_1%29%3Dn_2%20%2A%20sin%28%5Calpha%20_2%29)
Where ![n_{1} = 1, n_{2} = 1.33, \alpha _{2} = 40^o](https://tex.z-dn.net/?f=n_%7B1%7D%20%3D%201%2C%20n_%7B2%7D%20%3D%201.33%2C%20%5Calpha%20_%7B2%7D%20%3D%2040%5Eo)
=>
and
are the refractive indexes of the air and water respectively.
<u><em>Solution:</em></u>
=> 1 * sin (40) = 1.33 * sin(
)
=> sin
= ![\frac{sin 40^0}{1.33}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%2040%5E0%7D%7B1.33%7D)
=> sin
= 0.4821
=>
= 28.9 degrees
Answer:
The particle’s velocity is -16.9 m/s.
Explanation:
Given that,
Initial velocity of particle in negative x direction= 4.91 m/s
Time = 12.9 s
Final velocity of particle in positive x direction= 7.12 m/s
Before 12.4 sec,
Velocity of particle in negative x direction= 5.32 m/s
We need to calculate the acceleration
Using equation of motion
![v = u+at](https://tex.z-dn.net/?f=v%20%3D%20u%2Bat)
![a=\dfrac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv-u%7D%7Bt%7D)
Where, v = final velocity
u = initial velocity
t = time
Put the value into the equation
![a=\dfrac{7.12-(-4.91)}{12.9}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B7.12-%28-4.91%29%7D%7B12.9%7D)
![a=0.933\ m/s^2](https://tex.z-dn.net/?f=a%3D0.933%5C%20m%2Fs%5E2)
We need to calculate the initial speed of the particle
Using equation of motion again
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
![u=v-at](https://tex.z-dn.net/?f=u%3Dv-at)
Put the value into the formula
![u=-5.321-0.933\times12.4](https://tex.z-dn.net/?f=u%3D-5.321-0.933%5Ctimes12.4)
![u=-16.9\ m/s](https://tex.z-dn.net/?f=u%3D-16.9%5C%20m%2Fs)
Hence, The particle’s velocity is -16.9 m/s.