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kap26 [50]
4 years ago
14

Explain how surface and subsurface events are integral parts of the rock cycle.

Physics
1 answer:
vagabundo [1.1K]4 years ago
3 0
Example of surface events are erosion and weathering. Erosion is the carrying of a particle from one place to the other and weathering is the breaking down of particles. These processes help in rock formation because this allows physical changes (grouping together or breaking down) on a certain substance. Subsurface events are those which happened underground such as the flow of underground water which subsequently allow the deposition of minerals, etc. 
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Causing a collision while speeding puts points on your license
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The wavelength of an electron whose velocity is 1.7 Ã 104 m/s and whose mass is 9.1 Ã 10-28 g is ________ m. the wavelength of a
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3. Pedro threw a penny into a fountain and it sank to the bottom. Which of the following would explain
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4 years ago
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A car of mass 1000.0 kg is traveling along a level road at 100.0 km/h when its brakes are applied. Calculate the stopping distan
OleMash [197]

Explanation:

It is given that,

Mass of the car, m = 1000 kg

Speed of the car, v = 100 km/h = 27.77 m/s

The coefficient of kinetic friction of the tires, \mu_k=0.5

Let f is the net force acting on the body due to frictional force, such that,

-f=ma

a=\dfrac{-f}{m}

a=\dfrac{-\mu _k mg}{m}

a=\mu_k g

a=-0.5\times 9.8

a=-4.9\ m/s^2

We know that the acceleration of the car in calculus is given by :

v.dv=a.dx, x is the stopping distance

\int\limits^0_v {v.dv}=\int\limits^x_0 {a.dx}

\dfrac{v^2}{2}|_v^0=ax

0-(27.77)^2=-2\times 4.9x

On solving the above equation, we get, x = 78.69 meters

So, the stopping distance for the car is 78.69 meters. Hence, this is the required solution.

6 0
3 years ago
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