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guapka [62]
3 years ago
7

Identify the conjugate acid/base pairs in each of the following equations:

Chemistry
1 answer:
Valentin [98]3 years ago
6 0

Answer:

(a) Pair 1: H₂S and HS⁻

    Pair 2: NH₃ and NH₄⁺

(b) Pair 1: HSO₄⁻ and SO₄⁻

    Pair 2: NH₃ and NH₄⁺

(c) Pair 1: HBr and Br⁻

    Pair 2: CH₃O⁻ and CH₃OH

(d)  Pair 1: HNO₃ and NO₃⁻

     Pair 2: H₃O⁺

Explanation:

When an acid loses its proton (H⁺), a conjugate base is produced.

When a base accepts a proton (H⁺), it forms a conjugate acid.

(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.

    NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺

(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.

     The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.

(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.

   CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.

(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.

    H₂O gains a proton to form the conjugate acid H₃O⁺.

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POINTS!!!!
Setler79 [48]
C) 3 Moles
This is because of the molecular structure shown in the image

5 0
3 years ago
What is the mass of 11.4 L of NO2
kodGreya [7K]
At STP volume is 22.4 L

Molar mass NO₂ = 46.0 g/mol

1 mole ---------- 22.4 L
? mole ---------- 11.4 L

moles = 11.4 * 1 / 22.4

moles = 11.4 / 22.4

= 0.5089 moles of NO₂

Mass NO₂ :

moles NO₂ * molar mass

0.5089 * 46.0

= 23.4094 g of NO₂

hope this helps!

7 0
3 years ago
A total solar eclipse occurs because the moon can totally block the sun. If the moon was smaller or farther from earth, a total
Setler79 [48]

Answer:

both

Explanation:

id say that it could occur but also not as much. the moon would be smaller and further from the earth to where we would barely be able to see it. if the full moon is barely visible then im sure the total solar eclipse wouldn't be as noticeable as it is now. but thats just my opinion

6 0
2 years ago
When PCl5 solidifies it forms PCl4+ cations and PCl6– anions. According to valence bond theory, what hybrid orbitals are used by
Vlad1618 [11]

Answer:

sp³

Explanation:

Number of hybrid orbitals = ( V + S - C + A ) / 2

Where

H is the number of hybrid orbitals

V is the valence electrons of the central atom = 5

S is the number of single valency atoms = 4

C is the number of cations = 1

A is the number of anions = 0

For PCl₄⁺

Applying the values, we get:

H = ( 5+4-1+0) / 2

= 4

<u>This corresponds to sp³ hybridization.</u>

5 0
3 years ago
Read 2 more answers
What mass of f2 is needed to produce 120. g of pf3 if the reaction has a 78.1% yield?
lesya692 [45]

write the equation for the reaction

that is 6 F2 +P4 =4 PF3

find the theoretical mass that is

let the theoretical yield be represented by y

theoretical yield = 78.1/100 = 120/y

y= 153.6 grams

find the number of moles of  PF3

moles = mass/molar mass

= 153.6/87.97 =1.746 moles

by use of mole ratio between  F2 :PF3 which is 6:4 the moles of F2 is therefore= 1.746 x 6/4 = 2.62 moles

mass = moles x molar mass

= 1.746 moles x38 g/mol = 99.6 grams

6 0
3 years ago
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