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guapka [62]
3 years ago
7

Identify the conjugate acid/base pairs in each of the following equations:

Chemistry
1 answer:
Valentin [98]3 years ago
6 0

Answer:

(a) Pair 1: H₂S and HS⁻

    Pair 2: NH₃ and NH₄⁺

(b) Pair 1: HSO₄⁻ and SO₄⁻

    Pair 2: NH₃ and NH₄⁺

(c) Pair 1: HBr and Br⁻

    Pair 2: CH₃O⁻ and CH₃OH

(d)  Pair 1: HNO₃ and NO₃⁻

     Pair 2: H₃O⁺

Explanation:

When an acid loses its proton (H⁺), a conjugate base is produced.

When a base accepts a proton (H⁺), it forms a conjugate acid.

(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.

    NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺

(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.

     The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.

(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.

   CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.

(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.

    H₂O gains a proton to form the conjugate acid H₃O⁺.

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True or False? The fatal 1930 incident in Muese Valley, Belgium, was associated with leakage of toxic chemicals from a former du
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Answer:

FALSE                            

Explanation:

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PLEASE HELP ME ANSWER THESE QUESTIONS!
madam [21]

Answer:

1. 0.35 moles NaOH

2. 5.10x10^{-4} moles H_2SO_4

3. 505.4 g Pb

4. 1.46 g HCl (if that is wrong it's 1.5 g HCl due to sig figs)

5. 3.01x10^{23} atoms of Ag

6. 2x10^{-10} atoms of Cu

Explanation:

1. The mass of NaOH is 40g. 22.99(Na)+16(O)+1.01(H)=40 g

14 g NaOH *\frac{1 mol NaOH}{40 g NaOH} = 0.35 moles of NaOH

2. Mass of H_{2} SO_{4} = 2(1.01)+32.06+4(16) = 98.08

0.05 g H_2SO_4 ×\frac{1 mol H_2SO_4}{98.08g H_2SO_4} = 5.10 x10^{-4}

3. mass of Pb = 106.4 g

4.75 moles Pb×\frac{106.4 g Pb}{1 mol Pb} =505.4 g Pb

4. mass of HCl = 1.01 +35.45 = 36.36 g

0.04 mol HCl x \frac{36.46 g HCl}{1 mol HCl} = 1.456 = 1.5

5. 5.00 mol Ag x\frac{6.022x10^{23} atoms }{1mol Ag} = 3.01x10^{24} atoms

6. 3x10^{-10} moles Cu x\frac{6.022x10^{23} atoms}{1 mol Cu} = 1.8668x10^{14}= 2x10^{14} atoms of Cu

8 0
2 years ago
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