Explanation:
The solution of the lactic acd and sodium lactate is referred to as a buffer solution.
A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa. In this case, the weak acid is the lactic acid and the conjugate base is the sodium lactate.
Buffer solutions are generally known to resist change in pH values.
When a strong base (in this case, NaOH) is added to the buffer, the lactic acid will give up its H+ in order to transform the base (OH-) into water (H2O) and the conjugate base, so we have:
HA + OH- → A- + H2O.
Since the added OH- is consumed by this reaction, the pH will change only slightly.
The NaOH reacts with the weak acid present in the buffer sollution.
The answer is d. hope it helps
Answer:
Explanation:
1. find the molar mass (amu) of each element and add them to get the whole molar mass.
2. divide the 1 element molar mass with the whole molar mass
3. multiple by 100 and that gives you the % composition.
<h2><u><em>56-57: NaCl</em></u></h2>
1. Na(22.99amu) + Cl (35.453amu)=58.443
2(Na): 
= .393
2(Cl): 
= .607
3(Na): .393 * 100=39.3%
3(Cl): .607 * 100= 60.7%
<h2><u>58-60 </u>
<u /></h2>
1. K: (39.098)(2)=78.196
_ C: (12.011)(1)= 12.011
_O: (15.99)(3) = 47.997
78.196+12.011+47.997= 138.204
2:K: 
= .566 <u>Step </u>3: (.566)(100)= 56.6%
2: C: 
= .087 <u>Step 3</u>: (.087)(100)= 8.7%
2: O: 
= .347 <u>Step 3</u>: (.347)(100) = 34.7%
<h2>
61-62 
</h2>
1. Fe (55.845)(3)= 167.535
_ O (15.999)(4) = 63.996
167.535+63.996=231.531
2: Fe: 
= .724 Step 3: (.724)(100)= 72.4%
2: O : 
= .276 Step 3: (.276)(100) = 27.6%
<h2>63-65
</h2>
1.
C(12.011*3)=36.033
H(1.008*5)=5.04 + (1.008*3)=3.024 so its 8.064
O(15.999*3)=47.997
add them: 92.094
2: C: 
= .391 Step 3: (.391)(100) = 39.1%
2: H: 
= .088 step 3: (.088)(100) = 8.8%
2: O: 
= .521 step 3: (.521)(100) = 52.1%
To test for hydrogen, burn a candle near the suspected source of hydrogen. If you hear a squeaky pop sound, hydrogen is present because when hydrogen gas burns, it makes a squeaky pop sound.
