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inn [45]
3 years ago
13

2. Mercury-197 is used for kidney scans and has a half-life of 3 days. If 32 grams of

Chemistry
1 answer:
VLD [36.1K]3 years ago
8 0
<h3>Answer:</h3>

1 grams Mercury-197

<h3>Explanation:</h3>

From the question,

The radioisotope is Mercury-197

The half life of Mercury-197 is 3 days

Starting mass is 32 grams

Time taken is 15 days

We are required to calculate the final mass of the radioisotope after 15 days.

  • Note that, half life is the time taken by radioisotope to decay by half its original amount.
  • In this case, the half life of mercury-197 is 3 days, therefore, it takes three days for a mass of mercury-197 to decay by half its original mass.

Therefore, using the formula;

Final amount = Starting mass × (1/2)^n

where n is the number of half-lives (ratio of time to half life)

In our case, n = 15 days ÷ 3 days

                      = 5

Therefore;

Final mass = 32 g × (1/2)^5

                  = 32 g × 1/32

                 = 1 g

Therefore, the amount of mercury-197 in the shipment that will arrive is 1 g.

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Saltpeter is a compound made of potassium (k), nitrogen (n), and oxygen (o). every 100.00 g of saltpeter contains 38.67 g potass
xeze [42]
First, we need to compute the mass of oxygen found in 100 grams of saltpeter:
mass of oxygen = 100 - (mass of potassium + mass of nitrogen)
                          = 100 - (38.67 + 13.86)
                          = 100 - 52.53
mass of oxygen in 100 grams saltpeter = 47.47 grams

Now, we can use cross multiplication to find the mass of oxygen in 328 grams saltpeter as follows:
mass of oxygen = (328 x 47.47) / 100 = 155.7016 grams
5 0
3 years ago
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Which of the following metals would be the best for the new frying pan?
Rudik [331]

Answer:

Copper

Explanation:

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Manganese nodules are considered a valuable resource from the ocean floor because they are abundant and contain not only mangane
MAVERICK [17]

Answer: iron (oxides of iron)

Explanation: manganese nodules usually contain layers of iron and manganese oxides in a concentric arrangement and are called polymetallic nodules.

4 0
4 years ago
Lactose, C12H22O11, is a naturally occurring sugar found in mammalian milk. A 0.335 M solution of lactose in water has a density
Dmitry_Shevchenko [17]

The molality of the solution is 0.00037 m.

<h3>What is concentration?</h3>

The term concentration refers to the amount of solute in a solution.

We have the following information;

Molarity = 0.335 M

Density =  1.0432 g/mL

Temperature = 20 o C

The molality of the solution is obtained from;

m = 0.335 M ×  1.0432 g/mL/ 1000(1.0432 g/mL) - 0.335 M (342 g/mol)

m = 0.344/1043.2 - 114.57

m =  0.344/928.63

m = 0.00037 m

Learn more about molality of solution: brainly.com/question/4580605

5 0
3 years ago
How many grams of Ca(OH)2are required to make 1.5 L of a 0.81 M solution?
FrozenT [24]

Answer:

Mass = 90.28 g

Explanation:

Given data:

Mass of Ca(OH)₂ = ?

Volume of solution= 1.5 L

Molarity of solution = 0.81 M

Solution:

First of all we will calculate number of moles.

Molarity = number of moles / volume in L

by putting values,

0.81 M = Number of moles / 1.5 L

Number of moles = 0.81 M × 1.5 L

Number of moles = 1.22 mol

Mass of Ca(OH)₂ in gram:

Mass = number of moles × molar mass

Mass = 1.22 mol × 74.09 g/mol

Mass = 90.28 g

5 0
3 years ago
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