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3 years ago

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What is the uses of echoes

1 answer:

Anestetic [448]3 years ago

6 0

Answer:

Echoes are the reflection of sound from relatively flat object that is far enough away that you can discern the time difference. Echoes are used to measure distance, velocity, and the shape of objects. Echoes off gratings result in an unusual pinging sound

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All of the following could describe an individual with antisocial personality disorder except __________. A. impulsive B. manipu

Natali5045456 [20]

D. responsible

Explanation:

Individuals with antisocial personality disorder are not responsible. They are often aggressive, impulsive and quite manipulative.

Antisocial personality disorder is a mental disorder in which a person violates the rights of others without feeling any remorse for doing so.

People with such disorders have a high tendency of breaking rules and laws in the society.
They are often manipulative and tends to make the society favor them.
They carryout activities without a forethought i.e impulsive.
They live a chaotic and irresponsible life feeling not duty bound to the society.
People with this disorder can be aggressive too.

Often times, this problem can be remedied by therapy

learn more:

Psychological disorder brainly.com/question/4211983

#learnwithBrainly

7 0

3 years ago

Determine the gravitational potential energy, in kJ, of 3 m3 of liquid water at an elevation of 40 m above the surface of Earth.

melomori [17]

Explanation:

We will calculate the gravitational potential energy as follows.

$P.E_{1} = mgz_{1}$

$P.E_{1} = (\rho V)gz_{1}$

= $1000 kg/m^{3} \times 3 m^{3} \times 9.7 \times 40 m$

= 1164000 J

or, = 1164 kJ (as 1 kJ = 1000 J)

Now, we will calculate the change in potential energy as follows.

$\Delta P.E = mg(z_{2} - z_{1})$

= $\rho \times V \times g (z_{2} - z_{1})$

= $1000 \times 3 \times 9.7 (10 - 40)m$

= -873000 J

or, = -873 kJ

Thus, we can conclude that change in gravitational potential energy is -873 kJ.

4 0

2 years ago

Please help (will mark brainliest)

serg [7]

Answer:

if im not mistaken i think its d let me know if correct plz

7 0

2 years ago

Read 2 more answers

A car is up on a hydraulic lift at a garage. The wheels are free to rotate, and the drive wheels are rotating with a constant an

masya89 [10]

Answer:

Explanation:

Given

Wheels are rotating with constant angular velocity let say $\omega$

Presence of constant angular velocity show that there is no angular acceleration thus there is no tangential acceleration.

But any particle on the rim will experience a constant acceleration towards center called centripetal acceleration.

(a) yes, there will be tangential velocity which is given by

$v=r\cdot \omega$

where r=radial distance from center

(b)tangential acceleration

there would be no tangential acceleration as velocity is constant

(c)centripetal acceleration

Yes, there will be centripetal acceleration given by

$a_c=\omega ^2\times r$

7 0

3 years ago

Find the wavelength λ of the 80.0-khz wave emitted by the bat. express your answer in millimeters.

vfiekz [6]

Answer:

4.29 millimeters

Explanation:

Bats emit ultrasound waves: in air, ultrasound waves travel at a speed of

$v=343 m/s$

The frequency of the waves emitted by this bat is:

$f=80.0 kHz = 80,000 Hz$

Therefore we can find the wavelength of the wave emitted by the bat by using the relationship between speed, frequency and wavelength:

$\lambda=\frac{v}{f}=\frac{343 m/s}{80,000 Hz}=4.29\cdot 10^{-3} m=4.29 mm$

4 0

2 years ago