The car should have a velocity of 60 m/s to attain the same momentum as that of the truck of 2000 kg.
Answer:
Explanation:
Momentum is measured as the product of mass of object with the velocity attained by that object.
Momentum of 2000 kg truck = Mass × Velocity
Momentum of 2000 kg truck = 2000×30 = 60000 N
Similarly, the momentum of 1000 kg car will be 1000× velocity of the 1000 kg car.
Since, it is stated that momentum of 2000 kg truck is equal to the momentum of 1000 kg of car, then the velocity of 1000 kg of car can be determined by equating the momentum of car and truck.
Momentum of 2000 kg truck = Momentum of 1000 kg car
60000=1000×velocity of 1000 kg car
Velocity of 1000 kg car = 60000/1000=60 m/s
So, the car should have a velocity of 60 m/s to attain the same momentum as that of the truck of 2000 kg.
Answer:
Membrane potential
Explanation:
Membrane potential is describes the difference in electrical charge across a membrane.
The difference in potential between exterior and interior of the biological cell is known as Membrane potential.Generally it is denoted by millivolts like mV and varies from -80 V to -40 V.
So the answer is Membrane potential
Answer:
hmmmmm ill get back later
Explanation:
Answer:
6.0 ×
W/
Explanation:
From Wien's displacement formula;
Q = e A
Where: Q is the quantity of heat transferred, e is the emissivity of the surface, A is the area, and T is the temperature.
The emissive intensity =
= e
Given from the question that: e = 0.6 and T = 1000K, thus;
emissive intensity = 0.6 × 
= 0.6 × 1.0 × 
= 6.0 ×

Therefore, the emissive intensity coming out of the surface is 6.0 ×
W/
.
<span>Sea breeze can happen during hot summer days because of the
uneven heating rates of water and land.
The land surface heats up faster than the surface of the water during the
day. At this rate, the air above the
land grows warmer than the air atop the ocean. Warmer air is always lighter
than cooler air. As a consequence, warm air is pushed upward causing it to
rise. With this, warmer air rises over the land. As warm air rises over the
land, cooler air over the ocean flows over the land surface to change or
replace the rising warm air.</span>