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2 years ago

9

How long does it take an airplane to fly 5000 m if it maintains a speed of 240 meters per second?

1 answer:

kolbaska11 [484]2 years ago

8 0

Answer:

20 5/6 sec

Explanation:

To find the solution we divide 5000 by 240

However, when you see a problem, always try to simplify

5000/240=500/24=250/12=125/6

Now the division is much easier

20 5/6 sec

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2 years ago

A car travels 5 km due east, then 10 km due north, and then 5

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3 years ago

In a thundercloud there may be electric charges of 45.0 C near the top of the cloud and -45.0 C near the bottom of the cloud. Th

Gala2k [10]

Answer:

The electric force on the top charge is $F=3.44\times 10^6\ N$ .

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Let F is the electric force on the top charge. The electric force is given by the formula as :

$F=\dfrac{kq^2}{d^2}$

$F=\dfrac{9\times 10^9\times (45)^2}{(2300)^2}$

$F=3445179.58\ N$

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3 years ago

A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow

Oksana_A [137]

Answer:

a) $\omega=1.36rad/s$

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c) $F=705.6N$

Explanation:

a) The angular velocity is related to the centripetal acceleration by the formula $a_{cp}=\omega^2r$ , which for our purposes we will write as:

$\omega=\sqrt{\frac{a_{cp}}{r}}$

Since <em>we want this acceleration to be 1.5 times that due to gravity</em>, for our values we will have:

$\omega=\sqrt{\frac{1.5g}{r}}=\sqrt{\frac{(1.5)(9.8m/s^2)}{(8m)}}=1.36rad/s$

b) 1 rpm (revolution per minute) is equivalent to an angle of $2\pi$ radians in 60 seconds:

$1\ rpm=\frac{2\pi rad}{60s} =\frac{\pi}{30}rad/s$

Which means <em>we can use the conversion factor</em>:

$\frac{1\ rpm}{\frac{\pi}{30}rad/s}=1$

So we have (multiplying by the conversion factor, which is 1, not affecting anything but transforming our units):

$\omega=1.36rad/s=1.36rad/s(\frac{1\ rpm}{\frac{\pi}{30}rad/s})=12.99rpm$

c) The centripetal force will be given by Newton's 2nd Law F=ma, so on the centripetal direction for our values we have:

$F=ma=(48kg)(1.5)(9.8m/s^2)=705.6N$

8 0

3 years ago