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Nina [5.8K]
3 years ago
15

HELPPPPPPPPPPP omll i cant fail

Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

F(-2)=2

Step-by-step explanation:

F(x)=4x+10

F(-2)

F(-2)=4(-2)+10

           -8 +10

F(-2)= 2

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How do I solve it because it’s really difficult
dybincka [34]

The solution of the equation is x= 3 and y = 2

Step-by-step explanation:

Given,

-3x-4y = -17 and

-x-3y = -9

The system of equation can be rewritten as

3x+4y = 17 ------eq 1 and

x+3y = 9 ------ eq 2

To solve for x and y

Multiplying eq 2 by 3 we get,

3x + 9y = 27

or, 3x = 27-9y

Putting this value of x into eq 1 we get,

27-9y +4y = 17

or, -5y = 17-27

or, -5y = -10

or, y = 2

Now put y=2 in eq 2 we get,

x = 9 - 3(2)

= 3

Hence the solution is x = 3 and y = 2

6 0
3 years ago
Select correct answer
Sergio [31]

Answer:

The values of p in the equation are 0 and 6

Step-by-step explanation:

First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p

2

−7p−4=(2p+1)(p−4)

So then the equation looks like:

\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}

2p+1

p

−

(2p+1)(p−4)

2p

2

+5

=−

p−4

5

To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:

\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}

(2p+1)(p−4)

p

2

−4p

−

(2p+1)(p−4)

2p

2

+5

=−

(p−4)(2p+1)

10p+5

Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.

(p^2-4p)-(2p^2+5)=-(10p+5)(p

2

−4p)−(2p

2

+5)=−(10p+5)

Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p

2

−4p)−(2p

2

+5) first:

(p^2-4p)-(2p^2+5)=-p^2-4p-5(p

2

−4p)−(2p

2

+5)=−p

2

−4p−5

-p^2-4p-5=-10p+5−p

2

−4p−5=−10p+5

Combine like terms:

-p^2-4p+0=-10p−p

2

−4p+0=−10p

-p^2+6p=0−p

2

+6p=0

Factor:

p=0, p=6p

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