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Umnica [9.8K]
2 years ago
10

Find the number of ibuprofen molecules in a tablet containing 200.0 mg of ibuprofen (c13h18o2). express the amount to four signi

ficant figures.
Chemistry
2 answers:
nikitadnepr [17]2 years ago
8 0

\boxed{5.8383\times 10^{20} \text{ molecules}} of ibuprofen present in tablet that contains 200.0 mg of ibuprofen.

Further Explanation:

The formula to calculate moles of ibuprofen is as follows:

\text{Moles of ibuprofen}=\dfrac{\text{Mass of ibuprofen}}{\text{Molar mass of ibuprofen}}                   ...... (1)

Mass of ibuprofen is to be converted from mg to g. The conversion factor for this is as follows:

\text{1 mg}=10^{-3}\text{ g}

Therefore mass of ibuprofen can be calculated as follows:

\begin{aligned}\text{Mass of ibuprofen}&=(\text{200.0 mg})\left (\dfrac{10^{-3}\text{ g}}{1\text{ mg}}\right)\\&=0.2000\text{ g} \end{aligned}

The mass of ibuprofen is 0.2000 g.

The molar mass of ibuprofen is 206.29 g/mol.

Substitute 0.2000 g for mass of ibuprofen and 206.29 g/mol for molar mass of ibuprofen in equation (1).

\begin{aligned}\text{Moles of ibuprofen}&=\dfrac{\text{0.2000 g}}{\text{206.29 g/mol}}\\&=\text{0.0009695 mol}\end{aligned}

Avogadro's law states that one mole of substance has 6.022\times10^{23} molecules. Therefore molecules of ibuprofen that are present in 0.0009695 moles of ibuprofen can be calculated as follows:

\begin{aligned}\text{Molecules of ibuprofen}&=(\text{0.0009695 mol})\left(\dfrac{6.022\times10^{23}\text{ molecules}}{\text{1 mol}}\right)\\&={5.8383\times10^{20}\text{ molecules}\end{aligned}

Therefore {5.8383\times 10^{20} \text{ molecules}} of ibuprofen are contained in a tablet that has 200.0 mg of ibuprofen in it.

Learn more:

1. How many moles of Cl are present in 8 moles of \text{CCl}_4 ? brainly.com/question/3064603

2. Calculate the moles of ions in HCl solution: brainly.com/question/5950133

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: ibuprofen, 200.0 mg, 0.2000 g, Avogadro's law, moles, molecules, 5.8383*10^20 molecules, mass of ibuprofen, molar mass of ibuprofen, 6.022*10^23 molecules, mg, g, conversion factor, mass, molar mass, 206.29 g/mol, 0.0009695 moles, tablet, formula, 10^-3 g, 1 mg.

Musya8 [376]2 years ago
4 0

First let us calculate for the molar mass of ibuprofen:

Molar mass = 13 * 12 g/mol + 18 * 1 g/mol + 2 * 16 g/mol

Molar mass = 206 g/mol = 206 mg / mmol

 

Calculating for the number of moles:

moles = 200 mg / (206 mg / mmol)

moles = 0.971 mmol = 9.71 x 10^-4 moles

 

Using the Avogadros number, we calculate the number of molecules of ibuprofen:

Molecules = 9.71 x 10^-4 moles * (6.022 x 10^23 molecules / moles)

<span>Molecules = 5.85 x 10^20 molecules</span>

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(1) The number of grams needed of each fuel (C_2H_6)\text{ and }(C_4H_{10}) are 19.23 g and 20.41 g respectively.

(2) The number of moles of each fuel (C_2H_6)\text{ and }(C_4H_{10}) are 0.641 moles and 0.352 moles respectively.

(3) The balanced chemical equation for the combustion of the fuels.

C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O

C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O

(4) The number of moles of CO_2 produced by burning each fuel is 1.28 mole and 1.41 mole respectively.

The fuel that emitting least amount of CO_2 is C_2H_6

Explanation :

<u>Part 1 :</u>

First we have to calculate the number of grams needed of each fuel (C_2H_6)\text{ and }(C_4H_{10}).

As, 52 kJ energy required amount of C_2H_6 = 1 g

So, 1000 kJ energy required amount of C_2H_6 = \frac{1000}{52}=19.23g

and,

As, 49 kJ energy required amount of C_4H_{10} = 1 g

So, 1000 kJ energy required amount of C_4H_{10} = \frac{1000}{49}=20.41g

<u>Part 2 :</u>

Now we have to calculate the number of moles of each fuel (C_2H_6)\text{ and }(C_4H_{10}).

Molar mass of C_2H_6 = 30 g/mole

Molar mass of C_4H_{10} = 58 g/mole

\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{19.23g}{30g/mole}=0.641moles

and,

\text{ Moles of }C_4H_{10}=\frac{\text{ Mass of }C_4H_{10}}{\text{ Molar mass of }C_4H_{10}}=\frac{20.41g}{58g/mole}=0.352moles

<u>Part 3 :</u>

Now we have to write down the balanced chemical equation for the combustion of the fuels.

The balanced chemical reaction for combustion of C_2H_6 is:

C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O

and,

The balanced chemical reaction for combustion of C_4H_{10} is:

C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O

<u>Part 4 :</u>

Now we have to calculate the number of moles of CO_2 produced by burning each fuel to produce 1000 kJ.

C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O

From this we conclude that,

As, 1 mole of C_2H_6 react to produce 2 moles of CO_2

As, 0.641 mole of C_2H_6 react to produce 0.641\times 2=1.28 moles of CO_2

and,

C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O

From this we conclude that,

As, 1 mole of C_4H_{10} react to produce 4 moles of CO_2

As, 0.352 mole of C_4H_{10} react to produce 0.352\times 4=1.41 moles of CO_2

So, the fuel that emitting least amount of CO_2 is C_2H_6

5 0
3 years ago
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