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enyata [817]
3 years ago
14

What mass of sucrose, C12H22011, is needed to make 500.0 mL of a 0.200M solution?

Chemistry
1 answer:
NeX [460]3 years ago
7 0

Answer:

34.23 g

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

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The Arrhenius plot of the reaction has a downward slope of 1.5 x104. Calculate the time required to reduce the concentration of
madam [21]
1.5?10000 10% then add it up
4 0
2 years ago
What devices will you use to measure the mass and the volume in this experiment? (density)
bekas [8.4K]

Answer:

Methods for determining or delivering precise volumes include volumetric pipets and pycnometers; less precise methods include burets, graduated cylinders, and graduated pipets. In this experiment, you will measure masses and volumes to determine density. Four different metal cylinders are investigated.

Explanation:

8 0
2 years ago
How many grams of CO2 are produced from 51 g of CH4
Elina [12.6K]

Answer:

use the equation Mass= RFM*Moles

Explanation:

use your periodic table

and create a little table

3 0
3 years ago
Define an ideal gas and explain under which conditions you may reasonably approximate a real gas as an ideal gas. Also mention c
TEA [102]

Answer:

High temperature and low pressure

Explanation:

According to the kinetic molecular theory, gases are composed of small particles called molecules which are in constant motion.

At high temperature and low pressure, gas molecules possess high kinetic energy and move at high velocities hence intermolecular interaction is almost none existent and real gases approach the behavior of ideal gases.

5 0
2 years ago
A solution is made by adding 35.5 mL of concentrated hydrochloric acid ( 37.3 wt% , density 1.19 g/mL1.19 g/mL ) to some water i
erastova [34]

Answer:

1.73 M

Explanation:

We must first obtain the concentration of the concentrated acid from the formula;

Co= 10pd/M

Where

Co= concentration of concentrated acid = (the unknown)

p= percentage concentration of concentrated acid= 37.3%

d= density of concentrated acid = 1.19 g/ml

M= Molar mass of the anhydrous acid

Molar mass of anhydrous HCl= 1 +35.5= 36.5 gmol-1

Substituting values;

Co= 10 × 37.3 × 1.19/36.5

Co= 443.87/36.6

Co= 12.16 M

We can now use the dilution formula

CoVo= CdVd

Where;

Co= concentration of concentrated acid= 12.16 M

Vo= volume of concentrated acid = 35.5 ml

Cd= concentration of dilute acid =(the unknown)

Vd= volume of dilute acid = 250ml

Substituting values and making Cd the subject of the formula;

Cd= CoVo/Vd

Cd= 12.16 × 35.5/250

Cd= 1.73 M

7 0
3 years ago
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