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marshall27 [118]
3 years ago
15

Which of the following is a counterexample to "the sum of two numbers is always greater than either of the numbers"?

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0

Answer:

-6 +12

Step-by-step explanation:

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A water tank has a radius 5 feet and height 11 feet. How much water can it hold?
Semmy [17]

The water tank hold 863.50 ft^{3} of water.

<h3>What is Volume of cylinder?</h3>

The volume of a cylinder is the number of unit cubes (cubes of unit length) that can be fit into it. It is the space occupied by the cylinder as the volume of any three-dimensional shape is the space occupied by it.

The water tank is in the shape of cylinder whose radius = 5 feet

and, height= 11 feet

Volume of water tank =\pi r^{2} h

                                    = 3.14 * 5 * 5 * 11

                                    = 3.14*25*11

                                   = 863.50 ft^{3}

Hence the water tank hold 863.50 ft^{3} of water.

Learn more about Volume of cylinder here:

brainly.com/question/16788902

#SPJ1

6 0
2 years ago
Write the expression (x^4)^3 in simplest form.
Alexxandr [17]

Answer:

x\sqrt{3}

Step-by-step explanation:

4*3

6 0
4 years ago
Read 2 more answers
Solve the equation -x/6greaterthanequalto3
enot [183]

Answer (depending if the fraction is positive or negative):

  1. x ≥ 18
  2. x ≤ -18

Step-by-step explanation:

If the fraction is positive:

  1. Write it out: \frac{x}{6} \geq 3  
  2. Multiply each side by 6 to cancel out the 6 under x. It should now look like this: x ≥ 18

If the fraction is negative:

  1. Write it out: -\frac{x}{6} \geq 3  
  2. Multiply each side by -6 to cancel out the -6 under x. It should now look like this: x ≤ -18

I hope this helps!

3 0
3 years ago
Solve completely (all missing sides and all missing angles) using trig ratios or laws. Round to the nearest tenth.
hodyreva [135]

Answer:

Step-by-step explanation:

3. Use Cosine law to find the  length of the unknown side (PR)

q² = p² +  r² - 2prCos Q

q is the opposite side of ∠Q;  

p is the opposite side of ∠P; p = 33

r is the opposite sides of ∠R ; r = 67

q² = 33² + 67² -  2* 33*67 Cos 19°

    = 1089 + 4489 - 4422 * 0.95

     = 1089 + 4489 - 4200.9

    = 1377.1

q = √1377.1

q = 37.1

PR = 37.1

To find the angle use law of sin

\sf \dfrac{q}{Sin \ Q} =\dfrac{p}{Sin \ P}\\\\\\\dfrac{37.1}{Sin \ 19}=\dfrac{33}{Sin \ P} \\\\\\\dfrac{37.1}{0.33}=\dfrac{33}{Sin \ P}\\\\\\37.1* Sin \ P = 33 *0.33\\\\Sin \ P =\dfrac{33*0.33}{37.1}

Sin P = 0.3

P = Sin^{-1} 0.3\\

P = 17.5°

∠R = 180 - (19 + 17.5)

    = 143.5°

6 0
2 years ago
PLEASE HELP PLEASE PLEASE!!!!!!!!
nadya68 [22]

Answer:

SRO and QRO

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
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