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2 years ago

Write a number of grams between 10 and 20, and then write an equivalent amount in milligrams.

Mathematics

1 answer:

oksano4ka [1.4K]2 years ago

3 0

Answer:

15 grams and 15000 milligrams

Step-by-step explanation:

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Add a picture please

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2 years ago

Gary deposited $20 in a savings account earning 10% interest, compound annually. to the nearest cent, how much will he have in 3

Strike441 [17]

<h3>Answer: $26.62 </h3>

============================

Work Shown:

P = 20 is the amount deposited

r = 0.10 is the decimal form of the 10% interest rate

n = 1 means we compound 1 time per year (annually)

t = 3 is the number of years

Plug those four values into the compound interest formula below

A = P*(1+r/n)^(n*t)

A = 20*(1+0.1/1)^(1*3)

A = 20*(1+0.1)^(3)

A = 20*(1.1)^(3)

A = 20*1.331

A = 26.62

5 0

2 years ago

Read 2 more answers

Find the decimal equivalent of -12/5 and 6 1/2

Flura [38]

Answer:

-12/5 = -1 2/5 = -1.4 and 6 1/2 = 13/2 = 6.5

Step-by-step explanation:

4 0

1 year ago

Marjorie bought 24 bottles of juice. Each day she opens and drinks 2 of these bottles of juice. Which inequality represents the

Anika [276]

Answer:

2d≤24

Step-by-step explanation:

Total number of bottled juice bought = 24 bottles

Amount she drank each day = 2 bottles

To get the inequality to represent greatest number of days she can continue before she has to replenish her stock, we will say;

1 day = 2 bottles

d days = 24 bottles

Cross multiply

2 * d = 1 * 24

2d = 24

Since we want to know the greatest number of days she can continue before she has to replenish her stock, the <u>equal to </u>to sign will be replaced with<u> less than or equal to</u> sign as shown;

2d≤24

<em>This shows that the maximum number of days she can continue before replenishing is 12days. It cannot exceed</em>

6 0

2 years ago

A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat

AveGali [126]

Answer:

a) 68% probability that the sample mean will be within ±5 of the population mean.

b) 95% probability that the sample mean will be within ±10 of the population mean.

Step-by-step explanation:

To solve this problem, we have to understand the Empirical Rule and the Central Limit Theorem

Empirical Rule

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s= \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

Mean: $\mu = 200$

Standard deviation of the population: $\sigma = 50$

Size of the sample: $n = 100$

Standard deviation for the sample mean: $s = \frac{50}{\sqrt{100}} = 5$

a.What is the probability that the sample mean will be within ±5 of the population mean?

5 is one standard deviation from the mean.

By the Empirical Rule, 68% probability that the sample mean will be within ±5 of the population mean.

b.What is the probability that the sample mean will be within ±10 of the population mean?

10 is two standard deviations from the mean

By the Empirical Rule, 95% probability that the sample mean will be within ±10 of the population mean.

4 0

2 years ago