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BlackZzzverrR [31]
3 years ago
9

Does anyone know how to do common ion effect in chemistry?

Chemistry
1 answer:
pishuonlain [190]3 years ago
7 0

Answer:

no i do not sorry for you

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100 POINTS!!!
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1) Area of one side of each cube

The area of one side of each cube can be calculated by multiplying the length times the width:

A=L\cdot W

where

L = length

W = width

For cube A: L=1 cm, W=1 cm

So the area is: A_A = (1)(1)=1 cm^2

For cube B: L=2 cm, W=2 cm

So the area is: A_B=(2)(2)=4 cm^2

For cube C: L=3 cm, W=3 cm

So the area is: A_C=(3)(3)=9 cm^2

2) Surface area of each cube

The surface area of a cube is given by the sum of the areas of all its faces. Since a cube has 6 identical faces, this means that the total surface area is equal to 6 times the area of one face:

A=6 A_1

where

A_1 is the area of one face of the cube

For cube A, the area of one face is A_A=1 cm^2

So the surface area of cube A is

A'_A = 6A_A=6(1)=6 cm^2

For cube B, the area of one face is A_B=4 cm^2

So the surface area of cube B is

A'_B = 6A_B=6(4)=24 cm^2

For cube C, the area of one face is A_C=9 cm^2

So the surface area of cube C is

A'_C = 6A_C=6(9)=54 cm^2

3) Volume of each cube

The volume of a cube is obtained by multiplying its length, its width and its height:

V=L\cdot W \cdot H

Where:

L = length

W = width

H = height

Moreover for a cube, all the sides have equal length, so L=W=H

So the volume can be rewritten as

V=L^3

For cube A: L = 1 cm

So the volume is V_A=(1 cm)^3 = 1 cm^3

For cube B: L = 2 cm

So the volume is V_B=(2 cm)^3 = 8 cm^3

For cube C: L = 3 cm

So the volume is V_C = (3 cm)^3 = 27 cm^3

4) Ratio surface area/volume for each cube

In this part, we have to calculate the ratio between surface area and volume of each cube:

r=\frac{A}{V}

where

A is the surface area

V is the volume

For cube A, we have:

A_A = 6 cm ^2 (surface area)

V_A=1 cm^3 (volume)

So the ratio for cube A is:

r=\frac{6}{1}=6

For cube B, we have:

A_B = 24 cm ^2 (surface area)

V_B=8 cm^3 (volume)

So the ratio for cube B is:

r=\frac{24}{8}=3

For cube C, we have:

A_C = 54 cm ^2 (surface area)

V_C=27 cm^3 (volume)

So the ratio for cube C is:

r=\frac{54}{27}=2

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A sample of gas is in a sealed rigid cointaner that maintains a constant volume which changes occur between the gas particles wh
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A0 emission as there is an increase in energy

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