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3 years ago

A chemical reference book says that substance x is not soluble in water

1 answer:

7 0

The normal dividing line for soluble/not soluble is 0.1 M.

If a substance, as a saturated solution at room temp and pressure, cannot form a solution concentration of 0.1 M, then it is considered insoluble.

The 0.1 M figure was selected because _most_ substances are either well above that value or well below. Some substances (calcium hydroxide is one? not sure) come close to the 0.1 M dividing line but there are only a very few.
but most likely it wont mix

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Answer:

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Explanation:

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How can you use boiling point and solubility properties of a substance to seperate it from a mixture?

zhuklara [117]

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3 years ago

V2O5 + Ca = V + CaO balance the eqaution

andreyandreev [35.5K]

Answer: The balanced equation is $V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO$ .

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, $V_{2}O_{5} + Ca \rightarrow V + CaO$

Here, number of atoms on reactant side are as follows.

V = 2
O = 5
Ca = 1

The number of atoms on product side are as follows.

V = 1
O = 1
Ca = 1

In order to balance this equation, multiply Ca by 5 on reactant side. Multiply V by 2 and CaO by 5 on product side. Therefore, the equation can be rewritten as follows.

$V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO$

Now here, number of atoms on reactant side are as follows.

V = 2
O = 5
Ca = 5

The number of atoms on product side are as follows.

V = 2
O = 5
Ca = 5

Since, there are same number of atoms on both reactant and product side. So, the equation is now balanced.

Thus, we can conclude that the balanced equation is $V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO$ .

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3 years ago

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