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-BARSIC- [3]
3 years ago
13

Which

Mathematics
1 answer:
bogdanovich [222]3 years ago
5 0
Last one 1/4x
because the opposite of 1/4 is 4/1
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Based on the figure below, what is the equation for the relationship of x equals the number of rectangles and y equals the perim
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Answer:

Are you still there? Continue answering or we'll let someone else answer in: 19:35

Step-by-step explanation:

4 0
3 years ago
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Please help. Answer 4 and 5, please
Thepotemich [5.8K]
Asked and answered elsewhere.
brainly.com/question/8586522
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3 years ago
Part 1: Identify the vertex, focus, and directrix of each. Then sketch the graph.
Lina20 [59]

Answer:  \bold{1.\quad \text{Vertex}:(4,-1)\qquad \text{Focus}:\bigg(4,-\dfrac{9}{8}\bigg)\qquad \text{Directrix}:y=-\dfrac{7}{8}}

                \bold{2.\quad \text{Vertex}:(2,1)\qquad \text{Focus}:\bigg(\dfrac{9}{4},1\bigg)\qquad \text{Directrix}:y=\dfrac{7}{4}}            

<u>Step-by-step explanation:</u>

The vertex form of a parabola is y = a(x - h)² + k  or  x = a(y - k)² + h

  • (h, k) is the vertex
  • p is the distance from the vertex to the focus
  • -p is the distance from the vertex to the directrix

    \bullet\quad a=\dfrac{1}{4p}

1) y = -2(x - 4)² - 1     →      a = -2   (h, k) = (4, -1)

a=\dfrac{1}{4p}\quad \rightarrow \quad -2=\dfrac{1}{4p}\quad \rightarrow \quad p=-\dfrac{1}{8}\\\\\text{Focus = Vertex + p}\\\\.\qquad = \dfrac{-8}{8}+\dfrac{-1}{8}\\\\.\qquad =-\dfrac{9}{8}\qquad \rightarrow \qquad \text{Focus}=\bigg(4,-\dfrac{9}{8}\bigg)\\\\\\\text{Directrix: y=Vertex - p}\\\\.\qquad \qquad y=\dfrac{-8}{8}-\dfrac{-1}{8}\\\\.\qquad \qquad y=-\dfrac{7}{8}

*******************************************************************************************

2) x = (y - 1)² + 2     →      a = 1   (h, k) = (2, 1)

a=\dfrac{1}{4p}\quad \rightarrow \quad 1=\dfrac{1}{4p}\quad \rightarrow \quad p=-\dfrac{1}{4}\\\\\text{Focus = Vertex + p}\\\\.\qquad = \dfrac{8}{4}+\dfrac{1}{4}\\\\.\qquad =\dfrac{9}{4}\qquad \rightarrow \qquad \text{Focus}=\bigg(\dfrac{9}{4},1\bigg)\\\\\\\text{Directrix: x=Vertex - p}\\\\.\qquad \qquad x=\dfrac{8}{4}-\dfrac{1}{4}\\\\.\qquad \qquad x=\dfrac{7}{4}

6 0
3 years ago
By remainder theorem, find the remainder of p(x) when it is divided by g(x), where p(x)= x^3-2x^2-4x-1, g(x)= x+1
Anuta_ua [19.1K]

By the remainder theorem the remainder when dividing p(x) by x-a is p(a).

Dividing by x+1 means we want p(-1).

p(-1) = (-1)³ - 2(-1)² -4(-1) - 1 = -1 - 2 + 4 - 1 = 0

Answer: 0

They go in evenly so x+1 is a factor of p(x).

7 0
3 years ago
How many zeros does the function f(x) = x^2 - e^0.1x have?
dmitriy555 [2]
2
Since it was x to the two
7 0
4 years ago
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