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jek_recluse [69]
3 years ago
13

1 1/2 x 1/2 = ? help me por favor <3

Mathematics
1 answer:
leva [86]3 years ago
8 0

Answer:

3/4

Step-by-step explanation:

Let's break it down

1 1/2 is a mixed number

How do we find the fraction form of mixed numbers?

We multiply the denomiator of the fraction part with the integer part and add the current number on the numerator to get your new numerator. The denomiator stays the same.

So in the case of 1 1/2, our new numerator is 2 x 1 + 1 = 3.

Thus, the fraction version is 3/2. Now we need to mulitply this by 1/2

3/2 x 1/2. We just have to multiply the numerator and demoniator

3 x 1 is our numerator

2 x 2 is our denomiator

3/4 cannot be simplified because the numerator and denomiator are both relatively prime (numerator is not divisible by denomiator and vice versa)

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Answer:

I'm guessing you are wondering how many miles are in the distance. The answer would be 75

Step-by-step explanation:

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4 years ago
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Taking the square root of both sides gives two possible cases,

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or

9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1

Recall that

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

If \alpha=2x and \beta=\dfrac\pi4, we have

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so in the equations above, we can write

\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1

Then in the first case,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi

(where n is any integer)

\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi

\implies x=n\pi\text{ or }\dfrac\pi4+n\pi

and in the second,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi

\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi

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Then the solutions that fall in the interval [0,2\pi) are

x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4

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For the answer to the question above asking, w<span>hat was the price per can and the numbers of cans purchased each time?
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