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aev [14]
3 years ago
7

Factor -45x - 18 using the greatest common factor. Do not use spaces in your answer

Mathematics
1 answer:
Doss [256]3 years ago
3 0
Answer:
-9(5x+2)

Step by step explanation:
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Given f(x) and g(x) = k⋅f(x), use the graph to determine the value of k.
oksian1 [2.3K]

Answer:

-3 is the value of k in g(x)=kf(x)

Step-by-step explanation:

Both functions cross nicely at x=-3 so I'm going to plug in -3 for x:

g(x)=kf(x)

g(-3)=kf(-3)

To solve this for k we will need to find the values for both g(-3) and f(-3).

g(-3) means we want the y that corresponds to x=-3 on the curve/line of g.

g(-3)=-3

f(-3) means we want the y that corresponds to x=-3 on the curve/line of f.

f(-3)=1

So our equation becomes:

g(-3)=kf(-3)

-3=k(1)

-3=k

So k=-3.

8 0
3 years ago
Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
\\\\\\
\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\


\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
\\\\\\
\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
3 years ago
How tall is a building that casts a 61-fit shadow when the angle of elevation of the sun is 60 degrees?
VladimirAG [237]

Answer:

106 ft

Step-by-step explanation:

Assuming the shadow is measured along horizontal ground.

tanθ =opp/adj = building height/shadow length

building height = shadow length(tanθ)

h = 61tan60

h = 105.65509...

4 0
3 years ago
What's 67,000 rounded to the nearest ten thousand
Lunna [17]
70,000
Since 67 is closer to 70 than 60, you would choose 70. Insert 70 into the ten thousands place, and you get 70,000
hope this helps:)
4 0
4 years ago
Read 2 more answers
Solve for x.<br><br><br><br> -3x = -15<br><br> x = -5<br> x = -45<br> x = 5
Ugo [173]

Answer:

x=5

Step-by-step explanation:

its five because if you replace x with 5 you get 5*-3. which equals -15

3 0
3 years ago
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