How to do that? Thanks
1 answer:
9) We need to find the limit as x approaches 2 of f(x) - g(x).
When we are approaching a certain value, we are essentially finding values that are infinitesimally approaching x = 2, to the point where we find the exact value when x hits 2.
Thus, by substituting x = 2 into f(x) - g(x), we are finding the value at which the functions' difference hits x = 2.
![\lim_{x \to 2} [f(x) - g(x)] = \lim_{x \to 2}[\frac{3x + 2}{4} - x^{2} + 3]](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%202%7D%20%5Bf%28x%29%20-%20g%28x%29%5D%20%3D%20%5Clim_%7Bx%20%5Cto%202%7D%5B%5Cfrac%7B3x%20%2B%202%7D%7B4%7D%20-%20x%5E%7B2%7D%20%2B%203%5D)
Every other question repeats this process, so by applying the above process, your answers should come out smoothly.
Let me know if you need any more assistance, and I can guide you through them.
When we are approaching a certain value, we are essentially finding values that are infinitesimally approaching x = 2, to the point where we find the exact value when x hits 2.
Thus, by substituting x = 2 into f(x) - g(x), we are finding the value at which the functions' difference hits x = 2.
Every other question repeats this process, so by applying the above process, your answers should come out smoothly.
Let me know if you need any more assistance, and I can guide you through them.
You might be interested in
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
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