The correct answer is : The Organism belongs in Kingdom Fungi
The explanation:
1) because Fungi can be multicellular
2) most of them cannot move.
3) They can get food by releasing digestive juices into their environment.
Answer:
<h3>Density of the Gas</h3>
Explanation:
More molecules mean more hits against the container walls. Increasing the number of particles means you have increased the density of the gas. This third factor is part of the ideal gas law, which explains how these three factors -- temperature, volume and density -- interact with each other.
Answer : The ratio of the protonated to the deprotonated form of the acid is, 100
Explanation : Given,
pH = 6.0
To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
Now put all the given values in this expression, we get:
![6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=6.0%3D8.0%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
![\frac{[Deprotonated]}{[Protonated]}=0.01](https://tex.z-dn.net/?f=%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D%3D0.01)
As per question, the ratio of the protonated to the deprotonated form of the acid will be:
![\frac{[Protonated]}{[Deprotonated]}=100](https://tex.z-dn.net/?f=%5Cfrac%7B%5BProtonated%5D%7D%7B%5BDeprotonated%5D%7D%3D100)
Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100
The value given is called the Avogadro's number. It is the number of particles in every 1 mole of any substance. I think this is a trial and error process. Input 6.022x10^23 into your calculator. Add to this a number consisting of the maximum digit which is 9. Apparently, when 10×10¹³ is added, the display already changes. Therefore, the largest number would have to be 10×10¹².
The answer to your question is c
