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mel-nik [20]
3 years ago
12

Potassium chlorate (kclo3) decomposes in a reaction described by this chemical equation:2kclo3(s) → 2kcl(s) + 3o2(g)if 36.0 gram

s of potassium chlorate enter into this reaction, what is the total mass of the two products?
Chemistry
1 answer:
cricket20 [7]3 years ago
6 0
<span>If 36 gm of potassium chlorate enter into the reaction, the total mass of the two products will still be 36 gm because if there is only one reactant, the mass of the compounds after the reaction will be same that reactant based on the law of conservation of matter.</span>
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What are the major organic products are formed when the following compounds react with methylmagnesium bromide (CH3MgBr), follow
Sliva [168]

Answer:

Major organic products are- (a) propan-1-ol and (b) 2-methylpropan-2-ol

Explanation:

methyl magnesium bromide gives nucleophilic addition reaction with carbonyl group. Because methyl magnesium bromide is a strong nucleophile and carbonyl group is a strong electrophilic center.

Propanal contains an aldehyde group and propanone contains a ketone group. hence they both give nucleophilic addition with methyl magnesium bromide.

Dilute acid is added to protonate the alkoxide produced during nucleophilic addition.

Reactions are shown below.

6 0
3 years ago
B. if 6.73 g of na2co3 is dissolved in enough water to make 250. ml of solution, what is the molar concentration of sodium carbo
BARSIC [14]

Answer:- [Na_2CO_3]=0.254M , [Na^+]=0.508 M , [CO_3^2^-]=0.254M

Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.

Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL.  Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.

Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:

\frac{6.73gNa_2CO_3}{250.mL}(\frac{1mol}{105.99g})(\frac{1000mL}{1L})

= 0.254MNa_2CO_3

So, molarity of sodium carbonate solution is 0.254 M.

sodium carbonate dissociate to give the ions as:

Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^2^-

There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.

[Na^+]=2(0.254M) = 0.508 M

There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.

[CO_3^2^-]=0.254M


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4 years ago
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3 years ago
Ch
Aleksandr-060686 [28]

Answer:

Hello There!!

Explanation:

I believe the answer is how fast the molecules are vibrating.

hope this helps,have a great day!!

~Pinky~

8 0
3 years ago
How much heat energy is needed to heat 250 g of water from 200C to its boiling point and then completely vaporize it?
alexandr1967 [171]

Answer: 40.66kJ/mol.

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Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘

Explanation:Assuming that pressure is equal to 1 atm , boiling water at its boiling point implies providing it with enough heat to turn it from liquid at 100∘C to vapor at 100∘C

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nge of vaporization, Δ

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nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔH

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔHvap

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔHvap=

nge of vaporization, ΔHvap .For water at 100∘C , the enthalpy change of vaporization is equal toΔHvap=40.66 kJ/mol

8 0
3 years ago
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