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3 years ago

What must be true about a surface in order for diffuse reflection to occur?

Physics

1 answer:

balu736 [363]3 years ago

4 0

Answer:

carpet

Explanation:

Diffuse reflection is the reflection of light from a surface such that an incident ray is reflected at many angles rather than at just one angle as in the case of specular reflection.

The structure of carpet's surface is as shown. Thus it shows large amount of diffuse reflection.

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The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double th

Sati [7]

Answer:

it is double the temperature change of iron

3 0

2 years ago

A rock is dropped from a height of 3,245 m. If we ignore air resistance, how fast will it be travelling after it falls for 3.4 s

Marta_Voda [28]

Answer:

Explanation:

For a free falling object,it has constant acceleration and a changing velocity.

By using the velocity-time formula, the velocity can be obtained.

The height the rock travelled is the distance.

From,

Velocity (v) = Distance (d) / Time(t)

v = 3245m/3.4s

v = <u>954.4m/s</u>

That js the answer I got. Hope it's right.

3 0

3 years ago

You do 45 j of work in 3 seconds. how much power do you use

Oliga [24]

Answer:

Force= work done/time taken

so, 45j/3s

force= 15 N

Explanation:

8 0

3 years ago

How much work did the movers do (horizontally) pushing a 46.0-kg crate 10.4 m across a rough floor without acceleration, if the

creativ13 [48]

Answer:

The total work done by the mover is 2.81 kJ.

Explanation:

Given the 46 kg crate is displaced by 10.4 meters.

And the acceleration is zero. Also, $\mu_k=0.60$

let $P$ is applied force, $F_N$ is the net force, $m$ is the mass and $g=9.81\ m/s^2$

and $\mu_k=0.60$

$F_N=P- \mu_k\times mg$

As the acceleration is zero, the net force will also be zero.

$0=P- \mu_k\times mg\\P=\mu_k\times mg$ .

$P=0.6\times 46\times 9.81=270.76\ N$

Now, we know the work done is force times displacement.

So,

$W=P\times d\\W=270.76\times 10.4=2815.90\ J\\W=2.81\ kJ$

So, the total work done by the mover to displace 46 kg crate by 10.4 meters 2.81 kJ.

5 0

3 years ago

The cheetah starts at a position of 0.2 m and ends at a position of 45.6 m. What is the displacement of the cheetah during this

Andreyy89

Displacement is equals to final position minus initial position so final position is 45.6 m and initial position is 0.2 m so 45.6 - .2= 45.4

8 0

3 years ago