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Ostrovityanka [42]
4 years ago
11

What are four metals other than iron that can be made to exhibit magnetic properties? Fill in the blank. Every magnet has ______

_ unlike poles. The _______ within a magnet lies between the north and south poles. If the north pole of a bar magnet is brought near the _______ pole of another magnet, the two magnets will repel one another. A material that’s attracted by a magnet but doesn’t necessarily become a magnet itself is called a/an _______ material.
Physics
1 answer:
Morgarella [4.7K]4 years ago
4 0

Answer:

Four metals other than iron that can be made to exhibit magnetic properties are nickel, cobalt, manganese, and chromium.

two

neutral region

north

magnetic

Explanation:

PennFoster

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Gala2k [10]
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6 0
4 years ago
If you were to make a three-dimensional model of magnetic force using a magnet and magnetic field lines, which two characteristi
kkurt [141]

Answer:

- the Magnetic field lines will spread out of the north end of the magnet.

- the magnetic fields will three-dimensional and resemble a bubble.

Explanation:

- Usually, when drawing magnetic field lines, we start outwardly from the North pole to the South Pole. This same direction is also prevalent on the Earth due to the fact that the Earth functions as a giant magnet. Thus, one characteristic of the model is that the Magnetic field lines will spread out of the north end of the magnet.

- Another thing is that Magnetic field forces are usually driven as a result bubble like configuration which affects the objects that are in such a configuration. Thus, another characteristic of the model is that the magnetic fields will three-dimensional and resemble a bubble.

8 0
3 years ago
1. If two objects collide and one is initially at rest, is it possible for both to be at rest after the collision? Is it possibl
NeX [460]

Answer:

(a)If two objects collide and one is initially at rest, is it possible for both to be at rest after the collision?

No. Because if you have initial momentum P⃗ ≠0 , if both of the objects were at rest after the collision the total momentum of the system would be P⃗ =0 , which violates conservation of momentum

(b)Is it possible for only one to be at rest after the collision?

Yes, that is perfectly possible. It characteristically, happens when both objects are of the same mass. When two objects of the same mass collide and Kinetic energy is conserved (Perfectly Elastic collision) then the two objects interchange velocities.

8 0
2 years ago
HELP PLEASE PLEASE
marshall27 [118]
<h3>Answer:</h3>

Magnitude of Impulse: 30000 kg · m/s or 30000 N · s

Force on the Car: -6000 N

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality<u> </u>

<u>Physics</u>

<u>Momentum</u>

  • Momentum Equation: P = mv
  • Impulse Equation: J = FΔt
  • Law of Conservation of Momentum
<h3>Explanation:</h3>

<u>Step 1: Define</u>

Mass <em>m</em> = 1.50 × 10³ kg

Velocity <em>v</em> = 20 m/s east

Change in time Δt = 5.00 s

<u>Step 2: Find Magnitude</u>

  1. Substitute [Momentum]:                    P = (1.50 × 10³ kg)(20 m/s)
  2. Multiply:                                              P = 30000 kg · m/s

<u>Step 3: Find Force</u>

<em>We use the Law of Conservation of Momentum to find our break force acting upon the car.</em>

  1. Substitute [Impulse]:                    30000 kg · m/s = F(5.00 s)
  2. Rewrite:                                        30000 N · s = F(5.00 s)
  3. Divide 5 on both sides:               6000 N = F
  4. Rewrite:                                        F = 6000 N

Since the car is deaccelerating, the break force would be towards the west direction (negative as east is our positive direction).

∴ F = -6000 N

4 0
3 years ago
Read 2 more answers
A one-dimensional plane wall of thickness 2l= 100 mm experiences uniform thermal energy generation of q˙= 800 w/m3 and is convec
slega [8]

Answer:

The thermal conductivity of the wall = 40W/m.C

h = 10 W/m^2.C

Explanation:

The heat conduction equation is given by:

d^2T/ dx^2 + egen/ K = 0

The thermal conductivity of the wall can be calculated using:

K = egen/ 2a = 800/2×10

K = 800/20 = 40W/m.C

Applying energy balance at the wall surface

"qL = "qconv

-K = (dT/dx)L = h (TL - Tinfinity)

The convention heat transfer coefficient will be:

h = -k × (-2aL)/ (TL - Tinfinty)

h = ( 2× 40 × 10 × 0.05) / (30-26)

h = 40/4 = 10W/m^2.C

From the given temperature distribution

t(x) = 10 (L^2-X^2) + 30 = 30°

T(L) = ( L^2- L^2) + 30 = 30°

dT/ dx = -2aL

d^2T/ dx^2 = - 2a

4 0
3 years ago
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