Surface area of box=1200 cm²
<span>Volume of box=s²h </span>
<span>s = side of square base </span>
<span>h = height of box </span>
<span>S.A. = s² + 4sh </span>
<span>S.A. = surface area or 1200 cm², s²
= the square base, and 4sh = the four 'walls' of the box. </span>
<span>1200 = s² + 4sh </span>
<span>1200 - s² = 4sh </span>
<span>(1200 - s²)/(4s) = h </span>
<span>v(s) = s²((1200 - s²)/(4s)) </span>
<span>v(s) = s(1200 - s²)/4 . </span>
<span>v(s) = 300s - (1/4)s^3</span>
by derivating
<span>v'(s) = 300 - (3/4)s² </span>
<span>0 = 300 - (3/4)s² </span>
<span>-300 = (-3/4)s² </span>
<span>400 = s² </span>
<span>s = -20 and 20. </span>
again derivating
<span>v"(s) = -(3/2)s </span>
<span>v"(-20) = -(3/2)(-20) </span>
<span>v"(-20) = 30 </span>
<span>v"(20) = -(3/2)(20) </span>
<span>v"(20) = -30 </span>
<span>v(s) = 300s - (1/4)s^3 </span>
<span>v(s) = 300(20) - (1/4)(20)^3 </span>
<span>v(s) = 6000 - (1/4)(8000) </span>
<span>v = 6000 - 2000
v=4000</span>
Answer:
0.875
Step-by-step explanation:
9.85-8.975 equala 0.875
Answer:
Counselor's estimate isn't correct.
Step-by-step explanation:
Total number of students in university = 30,600
2% break 3 of the languages
Therefore, 2/100 × 30600 = 612 students break 3 of the languages in the University according to the counselor.
In a random sample of 240 students, 20 break 3 of the languages.
% = 20/240 × 100 = 8.33%
SinceTotal number of students = 30,600
Therefore, 30,600/240 = 127.5
Which means 127.5 × 20 = 2550.
Which means 2550 students break 3 of the languages as against the 612 students stated by the counselor.
Answer:
therefore, 33 divided by 13 equals 2 and 7 thirteenths (can be rewritten as 2 7/13)
Step-by-step explanation:
Long division:
13 33
13*2 = 26
33 - 26 = 7
we have: 33/13 = 2 r7
we know that we can rewrite the remainder as 7/13
therefore, 33 divided by 13 equals 2 and 7 thirteenths (can be rewritten as 2 7/13)
Answer:
24
Step-by-step explanation:
